Ask question

Ask question

All categories

3 years ago

15

Please help me. thank you.

1 answer:

Volgvan3 years ago

5 0

We know that WZ is a line, and all lines measure 180 degrees.

Therefore, Angle PWX + Angle PYX + Angle PYZ = 180 degrees. Plug in what we know:

$\sf 25\textdegree + 85\textdegree +x=180\textdegree$

Simplify:

$\sf 110\textdegree +x=180\textdegree$

Subtract 110 to both sides:

$\sf x=70\textdegree$

So angle PYZ is 70 degrees.

Angle ZX is equal to Angle PYX + PYZ.

$\sf 85\textdegree +70\textdegree =\boxed{\sf 155\textdegree}$

You might be interested in

Need help solving for X

Karolina [17]

Using the sine rule:

sinx/37 = sin42/31
sinx = 37 x sin42/31
x = (i dont have a calulator but use inverse sign to get this answer)

5 0

3 years ago

X=<br> 0 4<br> 06<br> 0 12<br> pls help !

irinina [24]

Answer:

maube 12

Step-by-step explanation:

i am not sure ..but try ur luck

5 0

3 years ago

The measure of an angle is 1°. What is the measure of its complementary angle?

Alex73 [517]

Answer:

89 degrees

Step-by-step explanation:

3 0

3 years ago

7. A lottery has a grand prize of $316, the winning group contains 3 members. If they

Luden [163]

Answer:

14348907

Step-by-step explanation:

5 0

3 years ago

A sports company wants to package a ball with a 1.5-inch radius in sets of two. They have two options: a cylinder or a square pr

guajiro [1.7K]

Step 1

Find the Volume of the two balls

we know that

the Volume of a sphere is equal to

$V=\frac{4}{3} \pi r^{3}$

In this problem we have

$r=1.5\ in$

Substitute

$V=\frac{4}{3} \pi 1.5^{3}=4.5\pi\ in^{3}$

so

the volume of the two balls is equal

$V=2*4.5\pi=9 \pi\ in^{3}$

Step 2

Find the volume of a cylinder

we know that

The Volume of a cylinder is equal to

$V=\pi r^{2}h$

In this problem we have

$r=1.5\ in$

$h=4*r=4*1.5=6\ in$

Substitute

$V=\pi (1.5^{2})(6)=13.5 \pi\ in^{3}$

Step 3

Find the amount of wasted space in the cylinder

Subtract the volume of the two balls from the volume of the cylinder

$13.5\pi\ in^{3}-9\pi\ in^{3}=4.5\pi\ in^{3}=14.14\ in^{3}$

Step 4

Find the volume of the square prism

The volume of the prism is equal to

$V=Bh$

where

B is the area of the base of the prism

h is the height of the prism

In this problem we have

$B=(2*1.5)^{2}=9\ in^{2}$ -----> the base is equal to the diameter

$h=4*r=4*1.5=6\ in$

Substitute

$V=9*6=54\ in^{3}$

Step 5

Find the amount of wasted space in the prism

Subtract the volume of the two balls from the volume of the prism

$54\ in^{3}-9\pi\ in^{3}=25.73\ in^{3}$

Step 6

Compare the amount of wasted space

the amount of wasted space in the cylinder is $14.14\ in^{3}$

the amount of wasted space in the prism is $25.73\ in^{3}$

Find the difference

$25.73\ in^{3}-14.14\ in^{3}=11.59\ in^{3}=11.6\ in^{3}$

The package that has the least amount of wasted space is the cylinder

therefore

<u>the answer is the option</u>

the cylinder because it has approximately 11.6 in.3 less wasted space than the prism

5 0

3 years ago

Read 2 more answers