He needs to play 23 more times. 785 / 35 = 23
He will have extra points but it will be enough to get the prize.
Hi! your answer should be 7.64 if I am not mistaken
Answer:
40%.
Step-by-step explanation:
Write it as a fraction then multiply by 100:
(36/90) * 100
= 3600/90
= 40%.
Answer: The sum is 3.
Step-by-step explanation:
If we have a parabola, y = a*x^2 + b*x + c
We want to find the point (x, y) that corresponds to the vertex of that parabola.
The vertex of the parabola is at x value:
x = -b/2a
in this case
a = 1, b = 0, c = 3
then our vertex is at:
x = -0/2*1 = 0
Now we evaluate y(x) in this value and get:
y(0) = a*0^2 + 3 = 3
Then the vertex is at the point (0, 3)
the sum of the coordinates of the vertex is:
S = 0 + 3 = 3
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
