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iogann1982 [59]
3 years ago
14

The sum of the coordinates of the vertex of the parabola at y = x2 + 3 is _____.

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
7 0

Answer: The sum is 3.

Step-by-step explanation:

If we have a parabola, y = a*x^2 + b*x + c

We want to find the point (x, y) that corresponds to the vertex of that parabola.

The vertex of the parabola is at x value:

x = -b/2a

in this case

a = 1, b = 0, c = 3

then our vertex is at:

x = -0/2*1 = 0

Now we evaluate y(x) in this value and get:

y(0) = a*0^2 + 3 = 3

Then the vertex is at the point (0, 3)

the sum of the coordinates of the vertex is:

S = 0 + 3 = 3

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Step-by-step explanation:

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\displaystyle y = \sqrt{x}(8x - 5)

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  1. Product Rule:                                                                                                  \displaystyle y' = \frac{d}{dx}[\sqrt{x}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]
  2. Rewrite:                                                                                                           \displaystyle y' = \frac{d}{dx}[x^{\frac{1}{2}}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]
  3. Basic Power Rule:                                                                                          \displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{1 - 1}
  4. Simplify:                                                                                                          \displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{0}
  5. Rewrite:                                                                                                           \displaystyle y' = \frac{1}{2x^{\frac{1}{2}}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8
  6. Multiply:                                                                                                           \displaystyle y' = \frac{8x + 5}{2x^{\frac{1}{2}}} + 8\sqrt{x}
  7. Rewrite:                                                                                                           \displaystyle y' = \frac{8x + 5}{2\sqrt{x}} + 8\sqrt{x}
  8. Add/Rewrite:                                                                                                   \displaystyle y' = \frac{24x - 5}{2\sqrt{x}}
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