Answer:
No.
Step-by-step explanation:
100 is not a perfect cube, as it cannot be written as x^3.
We can write 100 as (2^2)(5^2), which does not include any cubes.
100 is not a perfect cube
6
a
24
per abcf=20
2×(6+bc)=20
bc=4
A=(base +base /2)×h=
(5+3/2)×6=24
