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3 years ago

12

Find YZ. please help!!!

1 answer:

Ad libitum [116K]3 years ago

6 0

Your picture is a bit blurry. What is the equation on WX and on ZY?

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What is a fraction equivalent to -6/1

pashok25 [27]

Answer:

-18/3

Step-by-step explanation:

Multiply the denominator and numerator by the same whole number.

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3 years ago

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Ramandeep has a garden that is 6 and ⅔ feet by 7 and ⅘ feet. On the long side ¾ of the garden is planted and the remaining ¼ is

Ad libitum [116K]

1 2 3 4 your gonna get wrong hehehehehe

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3 years ago

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Maricela needs to write instructions for how to construct a regular hexagon inscribed in a circle. She begins by writing the fol

sammy [17]

Answer:

C

Step-by-step explanation

6 0

3 years ago

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S the expression x3•x3•x3 equivalent to x3•3•3

Artyom0805 [142]

Remember
(x^m)(x^n)=x^(m+n)
and difference of 2 perfect squres
(a²-b²)=(a-b)(a+b)
and sum or difference of 2 perfect cubes

so
(x^3)(x^3)(x^3)=x^(3+3+3)=x^9
so

x^9=3*3*x^3
x^9=9x^3
minus 9x^3 both sides
0=x^9-9x^3
factor
0=(x^3)(x^6-9)
factor difference of 2 perfect squraes
0=(x^3)(x^3-3)(x^3+3)
factor differnce or sum of 2 perfect cubes (force 3 into (∛3)³)
0=(x³)(x-∛3)(x²+x∛3+∛9)(x+∛3)(x²-x∛3+∛9)
set each to zero

x³=0
x=0

x-∛3=0
x=∛3

x²+x∛3+∛9=0 has no solution

x+∛3=0
x=-∛3

x²-x∛3+∛9=0 has no solution

so the solutions are
x=-∛3, 0, ∛3

3 0

3 years ago

50 POINTS WILL GIVE BRAINIEST. Which of the following numbers are irrational?

Otrada [13]

Answer:

$\sf \dfrac{\pi}{3}\:\:and\:\:\sqrt[\sf 3]{\sf 25}$

Step-by-step explanation:

<u>Definitions</u>

Integer: A whole number that can be positive, negative, or zero.

Rational Number: A number that can be expressed as the ratio of two integers (where the denominator does not equal zero).

Irrational Number: A real number that <u>cannot</u> be written as a rational number.

$\sf -8.2183 \times 10000=-82183$

$\implies \sf -8.2183=-\dfrac{82183}{10000}$

Therefore, -8.2183 can be expressed as a <u>rational number</u>.

π is an <u>infinite decimal</u>, so it cannot be expressed as a rational number.

$\textsf{Therefore},\:\dfrac{\pi}{3}\:\textsf{is irrational}.$

$\sqrt[\sf 3]{\sf 25}$ is an irrational number.

$\sf 9+ \sqrt{4}=9+\sqrt{2^2}=9+2=11$

As 11 can be expressed as ¹¹/₁ then 9 + √4 is <u>rational</u>.

<u>Conclusion</u>

Therefore, the numbers that are irrational are:

$\sf \dfrac{\pi}{3}\:\:and\:\:\sqrt[\sf 3]{\sf 25}$

8 0

2 years ago