Question

PLEASE HELP IF YOU CAN!

Answer 1

Answer:

its C

Step-by-step explanation:

Answer 2

$\bf \begin{array}{ccllll} term&value\\ \textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\ a_1&9.5\\ a_2&11.5\\ a_3&13.5\\ a_4&15.5\\ ...&... \end{array}\\\\ -----------------------------\\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term}\\ d=\textit{common difference} \end{cases}$

notice, the first term is 9.5
from there it goes to 11.5, well, how much is it being added to get 11.5?
well 9.5 + 2, is 11.5, so it was added 2 to 9.5

then it goes from 11.5 to 13.5, namely, 11.5+2 = 13.5
and then 13.5+2 = 15.5 and so on

so, the "common difference" or the common addition value, is 2
how do you find the nth term?

well  $\bf a_n=9.5+(n-1)2\iff a_n=9.5+2(n-1)$