Wrong,
You added when you were supposed to divide.
24/30 = 0.8
The equation is:
I=100+12J+5T+7S+5H-8M
The given information is that I=197, J=5, T=5, H=3, and M=3, and we’re trying to solve for the amount of shorts (S) he sold.
We can plug in the variables into the equation:
(197)=100+12(5)+5(5)+7S+5(3)-8(3)
After simplification:
197=100+60+25+7S+15-24
We can add/subtract the constants:
197=100+60+25+7S+15-24
We will add/subtract the constants:
197=176+7S
We will subtract 176 from both sides of the equation to cancel it out and isolate 7S:
197-176=176-176+7S
21=7S
We will divide 7 from both sides of the equation to cancel it out and isolate S:
21/7=7S/7
3=S or S=3 with the symmetric property of Equality applied.
Therefore, he sold 3 pairs of shorts
N<6 is the answer I think
Answer:
2/15
Step-by-step explanation:
Given that she have already read one-third of the book.
The fraction f of the book that will remain is;
f = 1 - 1/3 = 2/3
Then she finishes the book by reading the same amount each night for 5 nights
That implies she reads the remaining 2/3 of the book at equal rates for 5 nights.
Let x represent the fraction rate read per night;
5x = 2/3
Divide both sides by 5
x = 2/3 × 1/5
x = 2/15
Therefore, she reads 2/15 of the book every night for 5 nights.
Y = x^2 + 5x + 3
y = √(2x + 5)
Using a calculator, put equation 1 in y(sub1) and equation 2 in y(sub2).
Graph the equations and fin the point of intersection.
If using a TI 83/84 calculator, to find the point of intersection: 2nd CALC #5.
LETTER B
