Answer: It's a tie between f(x) and h(x). Both have the same max of y = 3
The highest point shown on the graph of f(x) is at (x,y) = (pi,3). The y value here is y = 3.
For h(x), the max occurs when cosine is at its largest: when cos(x) = 1.
So,
h(x) = 2*cos(x)+1
turns into
h(x) = 2*1+1
h(x) = 2+1
h(x) = 3
showing that h(x) maxes out at y = 3 as well
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Note: g(x) has all of its y values smaller than 0, so there's no way it can have a max y value larger than y = 3. See the attached image to see what this graph would look like if you plotted the 7 points. A parabola seems to form. Note how point D = (-3, -2) is the highest point for g(x). So the max for g(x) is y = -2
Answer:
x^2 + (y+1)^2 = 10^2
Step-by-step explanation:
Centre (p,q) = (0, -1)
radius, r = 10
General Equation of a circle
(x-p)^2 + (y-q)^2 = r^2
(x-0)^2 + (y- -1)^2 = 10^2
x^2 + (y+1)^2 = 10^2
Answer:
you put the points into the slope formula and solve : (y2-y1)/(x2-x1)
1. (4 -1) / (-2 -3)
3 / -5
2. (-1 -(-2)) / (5 - 0)
(-1 +2) / 5
1/ 5
Step-by-step explanation:
i hope this helped :)