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pashok25 [27]
2 years ago
7

Find the distance CD rounded to the nearest tenth C=(5,6) D=(2,2)

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
3 0
2,2 is 3,4 away from 5,6 and 3²+4²=25=5² so CD=5
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How many three-digit positive integers have three different digits and at least one prime digit?
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The number of three-digit positive integers that have three different digits and at least one prime digit are 7960.

The only two components in prime numbers are 1 and the number itself.

Any whole number greater than one is a prime number.

It has exactly two factors—1 and the actual number.

There is just one 2-digit even prime number.

Every pair of prime numbers is always a co-prime.

The product of prime numbers can be used to represent any number.

Three-digit positive integers that have three different digits and at least one prime digit = 3!*4!*10*9 = 7960

Learn more about prime numbers here:

brainly.com/question/145452

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2 years ago
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3 years ago
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3 years ago
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