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Julli [10]
3 years ago
13

What is the slope of the line?O slope = 1/3O slope = -3O slope = 3​

Mathematics
1 answer:
HACTEHA [7]3 years ago
6 0

Answer:

Slope = 3

Step-by-step explanation:

Slope is rise (vertical distance) over run (horizontal distance).

Our rise is equal to 3

Our run is equal to 1

So, slope = 3/1 = 3

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QUADRATIC FORMULA<br>X = ?​
wlad13 [49]

Answer:

quad form is (plus or minus)

Step-by-step explanation:

-b +-\sqrt{b^2-4ac}/2a

4 0
3 years ago
Read 2 more answers
Help me please!!!!!!!!!!!!!!!!!
iren [92.7K]

Answer:

A. x^6

Step-by-step explanation:

z =  {y}^{2}  =  {( {x}^{3} )}^{2}  =  {x}^{3 \times 2}  =  {x}^{6}

5 0
3 years ago
HELP PLS? BRAINLIST WILL BE REWARDED
GarryVolchara [31]

Answer:

Step-by-step explanation:

y = \frac{1}{5}x + 2

Find two points

When x = 0 ,  y = 0 + 2 = 2

D(0 , 2)

When x = 5;

    y=\frac{1}{5}*5+2= 1 + 2 = 3

E(5, 3)

Plot (0, 2 ) and (5 , 3) in the graph and join the points. This will be the line for the equation y =(1/5)x + 2

y = -x + 8

When x =4 ,  y = -4 + 8 = 4

A(4 , 4)

When x = 6 ;   y = -6 + 8 = 2

B(6 , 2)

Plot (4,4) and (6, 2) in the graph and join the points. This will be the line for the equation y = - x + 8.

This lines will intersect at  point (5,3) and  that point will be the solution of the equation.

8 0
3 years ago
Help answer asap pls ---------
Reika [66]

Answer:

d = 5

Step-by-step explanation:

We want to know what d would be when x = -1, so we can start off by plugging in -1 for x to get the following equation: \sqrt{8 - (-1)} = 2(-1)+d. On the left hand side, 2 negatives become a positive sign, so the -(-1) becomes a +1, and 8+1 would equal 9. On the right hand side, we just multiply 2 and -1 to get -2. So, the equation now looks like this: \sqrt{9} = d-2. We know that \sqrt{9} = 3, so we would get 3 = d-2. THen we would add 2 to both sides to get d = 5. Hope this helps!

8 0
3 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. y 2 ( y 2 − 4 ) = x 2 ( x
yawa3891 [41]

Answer:

y = -2

Step-by-step explanation:

To find the equation of the tangent we apply implicit differentiation, and then we take apart dy/dx

The equation is

y^2(y^2-4)=x^2(x^2-5)

implicit differentiation give us

\frac{d}{dx}[y^2(y^2-4)=x^2(x^2-5)]\\\\2y\frac{dy}{dx}(y^2-4)+y^2(2y\frac{dy}{dx})=2x(x^2-5)+x^2(2x)\\\\4y^3\frac{dy}{dx}-8y\frac{dy}{dx}=2x^3-10x+2x^3\\\\\frac{dy}{dx}=\frac{4x^3-10x}{4y^3-8y}

But we know that

m=\frac{dy}{dx}\\y=mx+b

Hence, for the point (0,-2) and by replacing for dy/dx

m=\frac{dy}{dx}_{(0,-2)}=\frac{4(0)+10(0)}{4(-2)^3-8(-2)}=0

Hence m=0, that is, the tangent line to the point is a horizontal line that cross the y axis for y=-2. The equation is:

y=(0)x+b = -2

HOPE  THIS HELPS!!

4 0
4 years ago
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