Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be:
miles/hour
and the <u>speed of Pratap against the current</u> will be:
miles/hour.
Suppose, the rate of Pratap in still water is
and the rate of current is
.
So, the equations will be........

Adding equation (1) and (2) , we will get......

Now, plugging this
into equation (1), we will get.....

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
Answer:14
Step-by-step explanation:
You have to find the reciprocal of the gradient - 1/2
And to do that just flip the sign and fraction:
-1/2
1/2
2/1
So the answer is,
Y = 2x + 11
Answer:
-1.83337261989
Step-by-step explanation:
(2 1/3)/y=-1.272727
2 1/3 = -1.272727y
y=-1.83337261989