Question

A bag contains 15 green, 18 yellow, and 16 orange balls. One ball is randomly selected. To the nearest percent, what is the probability of the event? Drag and drop the correct value into the box. P(yellow)=

Answer 1

37% hope this helps .............

Answer 2

Since the bag contains 15 green, 18 yellow, and 16 orange balls, the total number of balls in the bag are 15+18+16=49.

Therefore, the probability of the event that the drawn ball is yellow is given by:

P(yellow)=$\frac{Number of Yellow Balls}{Total Number of Balls}$

$\therefore P(Yellow)=\frac{18}{49}\times 100\approx36.73\approx37$%

Thus, the the probability of the event, to the nearest percent, that the drawn ball is yellow is 37%.