Answer:
750
Step-by-step explanation:
6(2k-3) is the answer to this problem.
make a distributive
take the 6 out of the equation and u have remaining 2k-3. 6(2k-3)
Answer:
Any one of these three works:
plane MOU
plane MNU
plane NOU
Step-by-step explanation:
A plane can be named by a single letter, such as L in this problem, or by any three non-collinear points that lie on the plane. Non-collinear points are points that do not all lie in a single line.
Points M, N, O, and U lie on plane L, so you can choose any 3 of the 4 points to name the plane with, but make sure all 3 points are non-collinear.
To name plane L with points, you cannot use points MNO together since they are collinear, but you can name it using point U plus any two of the points M, N, and O.
plane L can be named
plane MOU
plane MNU
plane NOU
Do not name it plane MNO
Here, we have to find the number of guests who can attend their weeding without exceeding the set budget of $10,000
Since the catering fee of $150 is waived, we do not consider this figure in our analysis
There is a constant which is the venue costs of $2,000 and a variable cost of $80 per guest for the reception.
Let us assume "X" guests arrive for the reception, so we can form the equation as shown below:
80X + 2,000 = 10,000 (Since the total budget for the wedding is $10,000)
80X = 8000
8X = 800
X =100
Therefore, Selena and Ronald can invite 100 guests for the wedding without going over their budget
