Answer and Step-by-step explanation:
The parent function, f(x) = |x|, has no transformations applied to it.
When the number is with the x, it translates the graph horizontally. <->
When the number is outside of the absolute box, it translates the graph vertically. ^ V
When the number is multiply the absolute box on the outside with the x inside, it scales the graph.
So, first lets apply the translations of horizontal and vertical shift.
The graph translated 1 units downwards.
The graph translates 2 units to the right.
g(x) = |x - 2| - 1
We subtract the 2 because that makes it go right, while if we added it would go left.
Now for the scale.
The lines have a slope of 
, so that is what we are multiplying.
<u> g(x) = </u><u>|x - 2| - 1</u>
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<u>^That is your transformed function.</u>
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<em><u>#teamtrees #PAW (Plant And Water)</u></em>
if its diameter is 14, then its radius is half that or 7.
![\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7 \end{cases}\implies \begin{array}{llll} V=\cfrac{4\pi (7)^3}{3}\implies V=\cfrac{1372\pi }{3} \\\\\\ \stackrel{using~\pi =3.14}{V\approx 1436.03} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D7%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20V%3D%5Ccfrac%7B4%5Cpi%20%287%29%5E3%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B1372%5Cpi%20%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7Busing~%5Cpi%20%3D3.14%7D%7BV%5Capprox%201436.03%7D%20%5Cend%7Barray%7D)
Answer:
C:25
Step-by-step explanation:
Hopefully this helps!
3a(4a^2 - 5a + 12)=12a^3-15a^2+36a (C)
Two lines are perpendicular between each other if their slopes fulfills the following property
where m1 and m2 represents the slopes of line 1 an 2, respectively.
To find the slope of a line we can write it in the form slope-intercept form
Our original line is
Then its slope is
Now we have to find the slope of the second line. Using the first property,
Then the second line has to have a slope of 8.
The options given to us are:
Then we have to determine which of these options have a slope of 8. To do that we write them in the slope-intercept form:
Once we have the options in the right form, we note that the only one of them that has a slope of 8 is the last one.
Then the line perpendicular to the original one is
