X=3
y=5
You have to cancel out either the x values or the y values (I chose y). You multiply both equations by particular numbers so either the x values or y values can be equal to each other, as well as positive or negative to each other. I multiplied -7y by 4 and 4y by 7, and got -28y and 28y. I then canceled those out. The numbers you multiply by also affects the rest of the equations, so I ended up with 48x=4 and -35x=35. After that, you combine like terms, which results in 13x=39. You divide 13 by both sides and you end up with x=3. To find y, all you have to do is plug in the x value to one of the equations, then solve for y. I resulted in y=5.
Hope this helped ^_^
Answer:
80 yd^2
Step-by-step explanation:
Since the formula for squares is s^2, we can use this to set up an equation, which is
s^2=400
If we square root this, we get
s=20
The perimeter formula for a square is 4s, so if we plug in, we end up with 80 yd^2
Answer:
Heyyy!!!!
The answer is 1.
Please read explanation it will definitely help you....
Step-by-step explanation:
Okay... Here it goes...
Basically, there is an exponent rule that says that anything to the power of 0 is 1.
I hope this helps!
Answer:
C
Step-by-step explanation:
5+2y+3z=5+3z+2yA
Intercambie los lados para que todos los términos de las variables estén en el lado izquierdo.
5+3z+2yA=5+2y+3z
Resta 5 en los dos lados.
3z+2yA=5+2y+3z−5
Resta 5 de 5 para obtener 0.
3z+2yA=2y+3z
Resta 3z en los dos lados.
2yA=2y+3z−3z
Combina 3z y −3z para obtener 0.
2yA=2y
Anula 2 en ambos lados.
yA=y
Divide los dos lados por y.
y
yA
=
y
y
Al dividir por y, se deshace la multiplicación por y.
A=
y
y
Divide y por y.
A=1
