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4 years ago

Find the surface area of a rectangular prism that has the following dimensions.

Mathematics

2 answers:

Shalnov [3]4 years ago

6 0

2(wl+hl+hw)=2·(14·2+11·2+11·14)=408

Alenkinab [10]4 years ago

3 0

Answer:

Late response, but the answer is 1,502

Step-by-step explanation:

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Does anyone know this answer for 5 and 6??

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3 years ago

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A ladder is leaning against a building. The distance from the bottom of the ladder to the building is 12 ft shorter than the len

Marysya12 [62]

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The answer for this question is 2 ft

Step-by-step explanation:

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2 years ago

A local pizza shop has a membership program for frequent buyers. The membership

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3 years ago

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To icrease an amount by 35% what single multiplier would u use

Pie

You would take your number, let's use 55, and multiply it by 0.35.

55 x 0.35 = 20.25

Then add that answer to your original number.

55 + 20.25 = 75.25

Your answer is 17.25.

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3 years ago

Some parts of California are particularly earthquake- prone. Suppose that in one metropolitan area, 25% of all homeowners are in

aleksandrvk [35]

Answer:

a. Binomial random variable (n=4, p=0.25)

b. Attached.

c. X=1

Step-by-step explanation:

This can be modeled as a binomial random variable, with parameters n=4 (size of the sample) and p=0.25 (proportion of homeowners that are insured against earthquake damage).

a. The probability that X=k homeowners, from the sample of 4, have eartquake insurance is:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{4}{k} 0.25^{0}\cdot0.75^{4}$

The sample space for X is {0,1,2,3,4}

The associated probabilties are:

$P(x=0) = \dbinom{4}{0} p^{0}(1-p)^{4}=1*1*0.3164=0.3164\\\\\\P(x=1) = \dbinom{4}{1} p^{1}(1-p)^{3}=4*0.25*0.4219=0.4219\\\\\\P(x=2) = \dbinom{4}{2} p^{2}(1-p)^{2}=6*0.0625*0.5625=0.2109\\\\\\P(x=3) = \dbinom{4}{3} p^{3}(1-p)^{1}=4*0.0156*0.75=0.0469\\\\\\P(x=4) = \dbinom{4}{4} p^{4}(1-p)^{0}=1*0.0039*1=0.0039\\\\\\$

b. The histogram is attached.

c. The most likely value for X is the expected value for X (E(X)).

Is calculated as:

$E(X)=np=4\cdot0.25=1$

6 0

3 years ago