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galben [10]
3 years ago
9

Find the surface area of a rectangular prism that has the following dimensions.

Mathematics
2 answers:
Shalnov [3]3 years ago
6 0
2(wl+hl+hw)=2·(14·2+11·2+11·14)=408
Alenkinab [10]3 years ago
3 0

Answer:

Late response, but the answer is 1,502

Step-by-step explanation:


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minimum value of function is   \frac{45}{8} .

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Given function represents a parabola.

Now, here coefficient of x^{2} is positive , so the parabola will be facing upwards and thus the function will be having a minimum.

Now, as we know that minimum value of a parabolic function occurs at

x = \frac{-b}{4a} .

Where , b represents the coefficient of x and a represents the coefficient of x^{2} .

here, a = 2 , b = -6

Thus \frac{-b}{4a} = \frac{6}{8}

                                            =  \frac{3}{4}

So, at x =  \frac{3}{4}  minimum value will occur and which equals

y = 2×\frac{9}{16} - \frac{18}{4} + 9 =  \frac{45}{8} .

Thus , minimum value of function is   \frac{45}{8} .

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