Answer:
127 &64
Step-by-step explanation:
x+y=191 eq(1) & x-y=63 eq(2)
x=63+y then put in the eq(1)
63+y+y=191
2y=191-63
y=64 then put in the eq(2)
x-y=63
x= 63+y
x=63+64
x=127
Well, on every test I have at a school and I believe most schools do this. You need at leasr 80% to pass. But to pass you'd most likely need 80% or 70%. But if you get an 80% you'll be sure to pass! I hope this helps you!
5(20) + 4y = 216
100 + 4y = 216
4y = 216 - 100
4y = 116
y = 116/4
y = 29.....so they sold 29 four-dollar yogurts + 20 five-dollar yogurts....for a total of 49 yogurts sold <==
Answer:
35 hotdogs
Step-by-step explanation:
You are running a concession stand at a basketball game. You are selling hotdogs and sodas.
Let the number of hot dogs be represented by x
The number of soda be represented by y
You sold a total of 87 hotdogs and sodas combined
x + y = 87
x = 87 - y
Each hotdog cost $1.50 and each soda cost $0.50. At the end of the night you made a total of $78.50.
Hence we have the equation:
$1.50 × x + $0.50 × y = $78.50
1.50x + 0.50y = 78.50
Substitute 87 - y for x
1.50(87 - y) + 0.50y = 78.50
130.5 - 1.50y + 0.50y = 78.50
Collect like terms
- 1.50y + 0.50y = 78.50 - 130.50
-1.00y = -52
y = -52/-1
y = 52 sodas
How many hotdogs did you sell?
Using the equation:
x = 87 - y
x = 87 - 52
x = 35 hotdogs
Hence, you sold 35 hotdogs
