Sample b is the control group because it’s the group not being tested and being kept the same.
Answer:
a. purple allele (C) = 0.609, pink allele (c) = 0.391
b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476
Explanation:
Given -
Purple flowers - 847
Pink flowers - 153
The frequency of recessive genotype i.e

Frequency of recessive allele i.e q is equal to

As per hardy Weinberg's first equilibrium equation -

Frequency of purple homozygous species

Number of purple homozygous species 
Number of pink homozygous species 
Heterozygous species is equal to

Answer:
Avoid using killed vaccine for administration.
Explanation:
Bruton's agammaglobulinemia may be defined as the X linked disorder that affects the immune system of an individual. This disease is mainly caused by the mutation in the gene responsible for coding the Bruton tyrosine kinase.
The children suffering from this disease require special immunization and some precaution must be followed before immunizing them. These patients are not allowed to immunizes with the live vaccines as these vaccines can evoke the immune response strongly and child may get infected by the disease. The individual should not given immunosuppressive drugs or corticosteroids.
Thus, the answer is avoid using killed vaccine for administration.
Answer;
(c) It can bond with other carbon atoms that are bonded to other molecules
Explaation;
-Carbon is the only element that can form so many different compounds because each carbon atom can form four chemical bonds to other atoms, and because the carbon atom is just the right, small size to fit in comfortably as parts of very large molecules.
-Carbon chains can bond with carbon rings to form very large, complex molecules. These large molecules can be made of many small molecules that are bonded together.
Answer:
The t-test
Explanation:
<em>The researcher should use a t-test to compare the two means and check if they are significantly different from each other.</em>
In using the t-test, both null (H0) and alternate (H1) hypothesis are made such that:
Thereafter, the value of t is calculated and compared to its critical value on the table. The formula for calculating the t goes thus:
where, Y1 = mean of population 1, Y2 = mean of population 2, S1 = variance of population 1, S2 = variance of population 2, n1 = number of individuals in population 1 and s2 = number of individuals in population 2.
<em>At the end of the day, if the calculated t value is more than the critical value of t, the H0 is rejected and it shows that the two means are significantly different. Otherwise, the H0 is accepted and this shows that there is not significant difference between the mean of population 1 and that of 2.</em>