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3 years ago

What property’s allow 5=b to be written as b=5

Mathematics

1 answer:

sineoko [7]3 years ago

8 0

Commutative Property allows 5=b to be written as b=5!

I hope this helped! Mark me Brainliest! :) -Raven❤️

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URGENT! WILL GIVE BRAINLIEST!!

IgorC [24]

Answer:

Option C) $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence

${\{m+b,2m+b,3m+b,4m+b,...}\}$

Step-by-step explanation:

Given infinite sequence is ${\{m+b,2m+b,3m+b,4m+b,...}\}$

Option B) $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence ${\{m+b,2m+b,3m+b,4m+b,...}\}$

Now verify $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is true for the given infinite sequence

That is put n=1,2,3,.. in the above function

$a_{n}=m-b+m(n-1)$

When n=1, $a_{1}=m-b+m(1-1)$

$=m-b+0$

$a_{1}=m-b\neq m+b$

When n=2, $a_{2}=m-b+m(2-1)$

$=m-b+m$

$a_{2}=2m-b\neq 2m+b$

When n=3, $a_{3}=m-b+m(3-1)$

$=m-b+2m$

$a_{3}=3m-b\neq 3m+b$

and so on.

Therfore $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence

${\{m+b,2m+b,3m+b,4m+b,...}\}$

Therefore option C) is correct

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4 years ago