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3 years ago

Find the HCF of 168 and 196.

Mathematics

2 answers:

julia-pushkina [17]3 years ago

5 0

Answer:

Step-by-step explanation:

168 = 2³ × 3 × 7

196 = 2² × 7²

HCF(168 ; 196) = 2² × 7 = 4 × 7 = 28

yan [13]3 years ago

3 0

Answer:

The HCF of 168 & 196 is 28

Step-by-step explanation:

The factors of 168 are: 1, 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, 168

The factors of 196 are: 1, 2, 4, 7, 14, 28, 49, 98, 196

The highest factor that both 168 and 196 share is 28

Hope this helps :D

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Anastasy [175]

Answer: 19.4

Step-by-step explanation:

Given

Profit is given in terms of the selling price

$y=-5x^2+194x-900$

to get the maximum price, differentiate y w.r.t x

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Put $\frac{\mathrm{d} y}{\mathrm{d} x}=0$ to get maximum value

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2 years ago

Hi guys can u also help me with this, i don’t understand a single thing of it

Bess [88]

HCF=Highest Common Factor-HCF of two or more numbers is the greatest factor that divides the numbers. For example, 2 is the HCF of 4 and 6.
LCM=Least Common Multiple-LCM is the smallest positive number that is a multiple of two or more numbers.

Answers:
1) 6
2) 12
3) 5
4) 3
5) 26
6) 15
7) 88

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1 year ago

Which statement is true? A.27/19<11/30 B.17/31>19/14 C.16/26>30/31 D.35/30<22/12

Mrac [35]

A. $\frac{27}{19}$

To find greater than or smaller than relation, we multiply the terms like (numerator of L.H.S with denominator of R.H.S and put the value on the left side. Then multiply the denominator of L.H.S with numerator of R.H.S and put the value on right side. Now compare the digits.)

So, solving A, we get 810<209 ... This is false

B. $\frac{17}{31}>\frac{19}{14}$

= 238>589 ..... This is false

C. $\frac{16}{26}>\frac{30}{31}$

= 496>780 .... This is false

D. $\frac{35}{30}$

= 420<660 ..... This is true

Hence, option D is true.

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3 years ago

A new club sent out 288 coupons to boost sales for next year's memberships. They provided 5 times as many to potential members t

Aliun [14]

Answer:

D. 48

Step-by-step explanation:

We don't know the numbers of coupons sent to existing members and to potential members, but we know a relationship between the number.

They sent 5 times as many coupons to potential members as they did to existing members.

Let x = number of coupons sent to existing members.

Then 5x = number of coupons sent to potential members.

The total number of coupons sent was x + 5x = 6x

The total number of coupons sent was 288.

Therefore, 6x must equal 288 giving us an equation with a single variable.

6x = 288

x = 48

Answer: 48

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