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3 years ago

–105 + (–14) + 34? I keep getting -75, can someone explain to me what I'm doing wrong?

2 answers:

5 0

It’s -85 I think there was just an error when you calculated it. -105+-14 is equal to -119. Than you add 34 to it to get -85.

mars1129 [50]3 years ago

3 0

Answer:

-85

Step-by-step explanation:

–105 + (–14) + 34

Take it step by step

-105 +-14

Factor out the negative so subtraction is easier

-(105+14) = -119

Then add 34

-119+34

Factor out the negative so subtraction is easier

-(119-34)

-85

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Round 7,883 to nearest thousand

Stels [109]

Answer:

8,000

Step-by-step explanation:

the nearest thousand is 8,000 as it is past 7,500.

6 0

3 years ago

Read 2 more answers

The ground-state wave function for a particle confined to a one-dimensional box of length L is Ψ=(2/L)^1/2 Sin(πx/L). Suppose th

Hitman42 [59]

Answer:

(a) 4.98x10⁻⁵

(b) 7.89x10⁻⁶

(c) 1.89x10⁻⁴

(d) 0.5

(e) 2.9x10⁻²

Step-by-step explanation:

The probability (P) to find the particle is given by:

$P=\int_{x_{1}}^{x_{2}}(\Psi\cdot \Psi) dx = \int_{x_{1}}^{x_{2}} ((2/L)^{1/2} Sin(\pi x/L))^{2}dx$

$P = \int_{x_{1}}^{x_{2}} (2/L) Sin^{2}(\pi x/L)dx$ (1)

The solution of the intregral of equation (1) is:

$P=\frac{2}{L} [\frac{X}{2} - \frac{Sin(2\pi x/L)}{4\pi /L}]|_{x_{1}}^{x_{2}}$

(a) The probability to find the particle between x = 4.95 nm and 5.05 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{4.95}^{5.05} = 4.98 \cdot 10^{-5}$

(b) The probability to find the particle between x = 1.95 nm and 2.05 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{1.95}^{2.05} = 7.89 \cdot 10^{-6}$

(c) The probability to find the particle between x = 9.90 nm and 10.00 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{9.90}^{10.00} = 1.89 \cdot 10^{-4}$

(d) The probability to find the particle in the right half of the box, that is to say, between x = 0 nm and 50 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5$

(e) The probability to find the particle in the central third of the box, that is to say, between x = 0 nm and 100/6 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{16.7} = 2.9 \cdot 10^{-2}$

I hope it helps you!

3 0

4 years ago

Which statement best describes the main theme of the short story?

stealth61 [152]

Answer:

c- people might not realize there words/actions are hurtful

8 0

3 years ago

Ln 2 - ln (3x + 2) =1

Westkost [7]

When you add 2 logs together, you get the log of the product.
When you subtract 2 logs, you get the log of the quotient.

Like this:

Ln(2) - Ln(3x+2) is the Ln(2/3x+2) .

So now you have Ln(2/3x+2) = 1

Raise 'e' to the power of
each side of the equation: (2/3x+2) = e¹

Multiply each side by (3x+2): 2 = (e) (3x+2)

Divide each side by 'e': 2/e = 3x + 2

Subtract 2 from each side: (2/e) - 2 = 3x

Divide each side by 3: x = [ (2/e) - 2 ] / 3

= approx. -0.421... (rounded)

I checked this by writing it into the original equation in place of 'x'.
That took my about 5 tries, but it finally checked OK.

Please. DON't use my answer unless you understand
where it came from.

7 0

4 years ago

Please help me with this

Alex_Xolod [135]

Answer:

it's an example related to your question

Step-by-step explanation:

Q. One number is 2 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 200, find the number

Answer:First number = x

One number = 2x

Third number = 100 + x

x + 2x + 100 + x = 200

Collect like terms

4x + 100 = 200

4x = 100

x = 25

First number = 25

One number = 50

Third number =125

Total= 200

Hope this helps.

7 0

3 years ago