Answer:
The worth of the car after 6 years is £2,134.82
Step-by-step explanation:
The amount at which Dan buys the car, PV = £2200
The rate at which the car depreciates, r = -0.5%
The car's worth, 'FV', in 6 years is given as follows;

Where;
r = The depreciation rate (negative) = -0.5%
FV = The future value of the asset
PV = The present value pf the asset = £2200
n = The number of years (depreciating) = 6
By plugging in the values, we get;

The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))
Answer:
De value of k is 9
Step-by-step explanation:
6,-1
b(1,3)
(k,8)
am using bodmas
a6-1×1=6a
b1×3=3b
abc=8
6a+3b+8=17-8
=9
X would be less than 6 2/3.
Answer:
x² - 64
Step-by-step explanation:
Given
(x + 8)(x - 8)
Each term in the second factor is multiplied by each term in the first factor, that is
x(x - 8) + 8(x - 8) ← distribute both parenthesis
= x² - 8x + 8x - 64 ← collect like terms
= x² - 64
Answer:
Always linear...
Decreases with successive trophic level