the table tells us that 4 students had no siblings 5 students had one sibling, 14 students had two siblings and so on
1 answer:
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1) 
Each marker cost 59 cents
2)
The old Big Almond Bag weighed 15 ounces. The new Big Almond Bag weighs 18 ounces.
Each marker cost 59 cents
2)
The old Big Almond Bag weighed 15 ounces. The new Big Almond Bag weighs 18 ounces.
Answer:
0.0668 = 6.68% probability that the height of a randomly selected tree is as tall as mine or shorter.
0.0228 = 2.28% probability that the full height of a randomly selected tree is at least as tall as hers.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
A tree of this type grows in my backyard, and it stands 132.3 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.
This is the pvalue of Z when X = 132.3. So
has a pvalue of 0.0668
0.0668 = 6.68% probability that the height of a randomly selected tree is as tall as mine or shorter.
My neighbor also has a tree of this type growing in her backyard, but hers stands 143.5 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers.
This is 1 subtracted by the pvalue of Z when X = 143.5. So
has a pvalue of 0.9772
1 - 0.9772 = 0.0228
0.0228 = 2.28% probability that the full height of a randomly selected tree is at least as tall as hers.