3 years ago

the table tells us that 4 students had no siblings 5 students had one sibling, 14 students had two siblings and so on

Mathematics

1 answer:

Hatshy [7]3 years ago

7 0

The answer is 8000383890

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Answer:

$\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}$

Step-by-step explanation:

Let's translate what you've written in words to an expression with mathematical symbols.

$\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}}$

To solve this, you need to multiply both the numerator and denominator with the conjugate of the denominator.

$\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}$

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