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Delicious77 [7]

2 years ago

8

An isosceles triangle has a perimeter of 34cm . The congruent sides measure (4x-1)cm . The length of the third side is x cm . Fi

nd X

1 answer:

kap26 [50]2 years ago

6 0

You know that the perimeter
P
is equal to
34
ans that it is the sum of the lengths of the three sides:
P
=
(
4
x
−
1
)
+
(
4
x
−
1
)
+
x
=
34
so:
4
x
−
1
+
4
x
−
1
+
x
=
34
isolate
x
:
9
x
=
34
+
2

9
x
=
36

x
=
36
9
=

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If ( 5^w )( 5^x ) = 5^y / 5^z , what is z in terms of w, x and y?

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b

Step-by-step explanation:

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Find the missing measures for the rectangle. l = _?_ w = 4.2 m A = 37.8 m2 P = _?_ A) 9 m; 26.4 m B) 14.7 m; 61.74 m C) 9 m; 13.

egoroff_w [7]

Answer:

The correct answer is A.

Step-by-step explanation:

The area of a rectangle can be calculated using the following formula:

$Ar=W . I$

If we know that the area measures $37.8 m^{2}$ and one side of the figure measures 4.2 m, we can say that:

$37.8m^{2}=4.2m. I$

We isolate the side we don't know:

$\frac{37.8m^{2}}{4.2m} = I\\9 m = I$

So I = 9 m

To know the perimter of a rectangle, we use the following formula:

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What is 4(-2)+(-3)(-5)?

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A food-packaging apparatus underfills 10% of the containers. Find the probability that for any particular 10 containers the numb

Maksim231197 [3]

Answer:

a) $P(X = 1) = 0.38742$

b) $P(X = 3) = 0.05740$

c) $P(X = 9) = 0.00000$

d) $P(X \geq 5) = 0.00163$

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 10 containers, so $n = 10$ .

A food-packaging apparatus underfills 10% of the containers, so $p = 0.1$ .

a) This is P(X = 1)

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

b) This is P(X = 3)

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

c) This is P(X = 9)

$P(X = 9) = C_{10,9}.(0.1)^{9}.(0.9)^{1} = 0.00000$

d) This is $P(X \geq 5)$ .

Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:

$P(X < 5) + P(X \geq 5) = 1$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.34868$

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X = 2) = C_{10,2}.(0.1)^{2}.(0.9)^{8} = 0.1937$

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

$P(X = 4) = C_{10,4}.(0.1)^{1}.(0.9)^{9} = 0.38742$

So

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.34868 + 0.38742 + 0.19371 + 0.05740 + 0.01116 = 0.99837$

Finally

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.99837 = 0.00163$

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Step-by-step explanation:

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