X actually equals the cube root of 6
![{x}^{3} - 6 = 0 \\ {x}^{3} = 6 \\ x = \sqrt[3]{6}](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B3%7D%20%20%20-%206%20%3D%200%20%5C%5C%20%20%7Bx%7D%5E%7B3%7D%20%20%3D%206%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B6%7D%20)
Answer:
5{z}^{3}-222-9{z}^{2}5z
3
−222−9z
2
Step-by-step explanation:
1 Collect like terms.
5{z}^{3}+(-224+2)-9{z}^{2}5z
3
+(−224+2)−9z
2
2 Simplify.
5{z}^{3}-222-9{z}^{2}5z
3
−222−9z
2
Done
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Answer:
the 15 year olds do
Step-by-step explanation:
For the first draw your probability is 3/14. Your second draw is 3/12.
Let me know if you have any other questions :)
