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4 years ago

Roger bowled 7 games last weekend. His scores are:

Mathematics

2 answers:

Sunny_sXe [5.5K]4 years ago

8 0

Answer:

I think it would be 155.

Step-by-step explanation:

You order the numbers from least to greatest, the number in the middle of all the others would be the median.

Ex: 1, 4, 6, 8 , 11, 13, 17 | 8 would be the median

Savatey [412]4 years ago

7 0

I think it’s 155 because if you line them up greatest to least it’s the number in the middle

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3 years ago

Is either x = 9 or x = 15 a solution to x-3 = 12?

tekilochka [14]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x 2 + 5

Arada [10]

Answer:

Width = 15 inches Length = 20 inches

Step-by-step explanation:

The area of a rectangle is calculated using the following formula.

$A = Lx$ (1)

Where L is the length and x is the width of the rectangle

In this case we know that the length of the rectangle is 5 inches greater than its width. This means that:

$L = x + 5$ (2)

Also The area of a rectangle can be represented by the equation $x^2 + 5x = 300$

so to find the width x we solve the equation

$x^2 + 5x -300=0$ (3)

For an equation of the form $ax ^ 2 + bx + c = 0$ the quadratic formula is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case note that:

$a=1\\b=5\\c=-300$

Then:

$x=\frac{-5\±\sqrt{(5)^2-4(1)(-300)}}{2(1)}$

$x=\frac{-5\±\sqrt{25+1200}}{2}$

$x=\frac{-5\±\sqrt{1225}}{2}$

$x=\frac{-5\±35}{2}$

$x_1=\frac{-5+35}{2}$ → $x_1=15$

$x_2=\frac{-5-35}{2}$ → $x_2=-20$

We take the positive solution $x=15\ in$

Now we use equation (2) to find L

$L = x + 5$

$L = 15 + 5$

$L = 20\ in$

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4 years ago

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