Answer:
Width = 15 inches Length = 20 inches
Step-by-step explanation:
The area of a rectangle is calculated using the following formula.
(1)
Where L is the length and x is the width of the rectangle
In this case we know that the length of the rectangle is 5 inches greater than its width. This means that:
(2)
Also The area of a rectangle can be represented by the equation ![x^2 + 5x = 300](https://tex.z-dn.net/?f=x%5E2%20%2B%205x%20%3D%20300)
so to find the width x we solve the equation
(3)
For an equation of the form
the quadratic formula is:
![x=\frac{-b\±\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5C%C2%B1%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
In this case note that:
![a=1\\b=5\\c=-300](https://tex.z-dn.net/?f=a%3D1%5C%5Cb%3D5%5C%5Cc%3D-300)
Then:
![x=\frac{-5\±\sqrt{(5)^2-4(1)(-300)}}{2(1)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-5%5C%C2%B1%5Csqrt%7B%285%29%5E2-4%281%29%28-300%29%7D%7D%7B2%281%29%7D)
![x=\frac{-5\±\sqrt{25+1200}}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-5%5C%C2%B1%5Csqrt%7B25%2B1200%7D%7D%7B2%7D)
![x=\frac{-5\±\sqrt{1225}}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-5%5C%C2%B1%5Csqrt%7B1225%7D%7D%7B2%7D)
![x=\frac{-5\±35}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-5%5C%C2%B135%7D%7B2%7D)
→ ![x_1=15](https://tex.z-dn.net/?f=x_1%3D15)
→ ![x_2=-20](https://tex.z-dn.net/?f=x_2%3D-20)
We take the positive solution ![x=15\ in](https://tex.z-dn.net/?f=x%3D15%5C%20in)
Now we use equation (2) to find L