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elena55 [62]
3 years ago
8

The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x 2 + 5

x = 300. What are the measures of the width and the length? Width = a0 inches Length = a1 inches
Mathematics
1 answer:
Arada [10]3 years ago
8 0

Answer:

Width = 15 inches             Length = 20 inches

Step-by-step explanation:

The area of a rectangle is calculated using the following formula.

A = Lx   (1)

Where L is the length and x is the width of the rectangle

In this case we know that the length of the rectangle is 5 inches greater than its width. This means that:

L = x + 5   (2)

Also The area of a rectangle can be represented by the equation x^2 + 5x = 300

so to find the width x we solve the equation

x^2 + 5x -300=0   (3)

For an equation of the form ax ^ 2 + bx + c = 0 the quadratic formula is:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case note that:

a=1\\b=5\\c=-300

Then:

x=\frac{-5\±\sqrt{(5)^2-4(1)(-300)}}{2(1)}

x=\frac{-5\±\sqrt{25+1200}}{2}

x=\frac{-5\±\sqrt{1225}}{2}

x=\frac{-5\±35}{2}

x_1=\frac{-5+35}{2}  →  x_1=15

x_2=\frac{-5-35}{2}  →   x_2=-20

We take the positive solution x=15\ in

Now we use equation (2) to find L

L = x + 5

L = 15 + 5

L = 20\ in

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<h3>What is residual value?</h3>

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Points and their residual values are shown in the table. A 3-column table with 5 rows.

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Learn more about the residual value here;

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6 0
2 years ago
Which area model represents 0.4 x 0.7 = 0.28?​
sammy [17]

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Step-by-step explanation:

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2 years ago
4x+(x-y/8)=17 and 2y+x-(5y+2/4)=2 by using elimination method
vladimir2022 [97]

Answer:

x=811/238, y=36/119. (811/238, 36/119).

Step-by-step explanation:

4x+(x-y/8)=17

2y+x-(5y+2/4)=2

-----------------------

4x+x-y/8=17

5x-y/8=17

40x-y=136

y=40x-136

------------------

2y+x-5y-2/4=2

2y-5y+x-1/2=2

-3y+x=2+1/2

-3y+x=4/2+1/2

-3y+x=5/2

-3(40x-136)+x=5/2

-120x+408+x=5/2

-119x=5/2-408

-119x=5/2-816/2

-119x=-811/2

119x=811/2

x=(811/2)/119

x=(811/2)(1/119)=811/238

y=40(811/238)-136

y=16220/119-136

y=36/119

x=811/238, y=36/119.

4 0
3 years ago
The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th
choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

f_x(x) = \dfrac{1}{1500} ; o \le x \le   \  1500

The function of the insurance is:

I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \  \ \ \ 250 \le x \le 1500}} \right.

Hence, the variance of the insurance can also be an account forum.

Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2

here;

E[I(x)] = \int f_x(x) I (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}

\dfrac{5}{12} \times 1250

Similarly;

E[I^2(x)] = \int f_x(x) I^2 (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}

\dfrac{5}{18} \times 1250^2

∴

Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]

Finally, the standard deviation  of the insurance payment is:

= \sqrt{Var(I(x))}

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≅ 404

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3 years ago
The mode of 100 120 120 140 140 100
Monica [59]

Answer:

100, 120, 140

Step-by-step explanation:

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7 0
3 years ago
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