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miskamm [114]
3 years ago
7

A tutor invited 2 students to a study group. Those 2 students each invited

Mathematics
1 answer:
kaheart [24]3 years ago
8 0
Hello, CptnSkippy! The answer to your question is 14 students were invited in total! To get the answer, you can do 2 x 2=4 and 4 x 2 which is 8. now you can draw a picture to this too. good luck and hope you get a good grade for your homework
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Jared bought eighteen doughnuts to share with his coworkers. If each doughnut cost c cents, which expression represents his tota
Oduvanchick [21]
Wait, how many cents?
7 0
1 year ago
Suppose that F(x) = x3 and G(x) = -4x3-5. Which statement best compares the graph of G(x) with the graph of F(x)?
lara31 [8.8K]

Answer:

Answer is B

Step-by-step explanation:

F(x) is first stretched by factor 4 from '4x³';

It is then reflected in the x-axis, since it is '-4x³';

Lastly, it is shifted down 5 units, because of the '-5'.

5 0
3 years ago
A ball is launched into the sky at 272 feet per second from the roof of a skyscraper 1,344 feet tall. The equation for the ball’
xz_007 [3.2K]

When the ball is in the ground, its height is basically equal to zero thus making our equation,

<span>    -16t^2 + 272t + 1344 = 0</span>

Simplifying the equation will give us,

<span>  - t^2 + 17t + 84 = 0 or t^2 – 17t – 84 = 0</span>

Factoring out the equation will give us,

<span>   (t – 21)(t + 4) = 0</span>

Thus, t = 21 or t = -4. -4 is an extraneous root. Thus, the answer is t = 21.

<span>Answer: 21 seconds</span>

5 0
3 years ago
A study conducted an experiment with 22,000 women over 10 years to investigate whether a high-stress job leads to heart problems
solniwko [45]
The sample of the group would be the 22,000 participants.
3 0
3 years ago
What is the area of this polygon? Enter your answer in the box. units²
Gemiola [76]

Answer:

The area of the polygon is 39\:units^2

Step-by-step explanation:

Sketch the polygon to obtain the figure in the attachment.

The polygon can then be divided into a rectangle and a triangle.

The area of the polygon

=|VE|\times |DE|+\frac{1}{2}\times |DE|\times |AM|

We use the absolute value method to find the lengths

=|3--2|\times |3--3|+\frac{1}{2}\times|3--3|\times |5-2|

=5\times 6+\frac{1}{2}\times 6\times 2

=30+9

=39\:units^2

4 0
3 years ago
Read 2 more answers
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