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4 years ago

Solve x/8+5/2+=3/2 what does x equal?

Mathematics

1 answer:

n200080 [17]4 years ago

8 0

Step-by-step explanation:

$\frac{x}{8} + \frac{5}{2} = \frac{3}{2}$

by taking L.C.M

$\frac{2x + 40}{8} = \frac{3}{2}$

$cross \: the \: values$

$2(2x + 40) = 8 \times 3$

$4x + 80 = 24$

$4x = 24 - 80$

$4x = - 56$

$x = \frac{ - 56}{4}$

$x = - 14$

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*<br> 4. Find the measure of each angle<br> Please help need answers ASAP

nekit [7.7K]

Answer:

55°, 125°

Step-by-step explanation:

angle EFG = 180°

angle EFH + angle GFH = angle EFG (Colinearity)

substitute the values,

6x - 5 + 12x + 5 = 180°

18x = 180°

(÷18)

x = 10

substitute values of x in both the requires angles,

angle EFH

= (6 × 10) -5

= 55°

angle GFH

= (12 × 10) + 5

=125°

to check,

55° + 125° = 180°

6 0

3 years ago

The soccer team collected $800 at a car wash fundraiser. They charged $5.00 for small vehicles and $10.00 for larger vehicles. T

Flauer [41]

Answer:

Step-by-step explanation:

Do 60 × 10.00 to get 600. Then do 800-600 to get 200. Then do 200÷5.00 to get 40.

4 0

3 years ago

Hey I need helping with solving thank you

Marrrta [24]

Answer:

the answer to this equation is c (10)

6 0

3 years ago

If f(x)=3/x+2-square root of x-3 what is f(19)

jasenka [17]

Answer:

-27/7

Step-by-step explanation:

Replace x with 19,

f(19)=3/(19+2) - root(19-3)

=3/21 - root(16)

=1/7 - 4

=1/7 - 28/7

= -27/7

5 0

3 years ago

If an arrow is shot upward on Mars with a speed of 62 m/s, its height in meters t seconds later is given by y = 62t − 1.86t². (R

Soloha48 [4]

Answer:

Approximately $58.28\; \rm m \cdot s^{-1}$ .

Step-by-step explanation:

The velocity of an object is the rate at which its position changes. In other words, the velocity of an object is equal to the first derivative of its position, with respect to time.

Note that the arrow here is launched upwards. (Assume that the effect of wind on Mars is negligible.) There would be motion in the horizontal direction. The horizontal position of this arrow will stays the same. On the other hand, the vertical position of this arrow is the same as its height: $y = 62\, t - 1.86\, t^2$ .

Apply the power rule to find the first derivative of this $y$ with respect to time $t$ .

By the power rule:

the first derivative of $t$ (same as
the first derivative of $t^2$ (same as $t$ to the second power) with respect to

Therefore:

$\begin{aligned}\frac{dy}{d t} &= \frac{d}{d t}\left[62 \, t - 1.86\, t^2\right] \\ &= 62\,\left(\frac{d}{d t}\left[t\right]\right) - 1.86\, \left(\frac{d}{d t}\left[t^2\right]\right) \\ &= 62 \times 1 - 1.86\times\left(2\, t) = 62 - 3.72\, t\end{aligned}$ .

In other words, the (vertical) velocity of this arrow at time $t$ would be $(62 - 3.72\, t)$ meters per second.

Evaluate this expression for $t = 1$ to find the (vertical) velocity of this arrow at that moment: $62 - 3.72 \times 1 =58.28$ .

6 0

3 years ago

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