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3 years ago

What is the selling price if the original cost is $145 and the markup is 150%? PLEASE HELP!! :(

1 answer:

3 0

It’s 362.50 you just add 145 for the 100% and get 290 then for the 50% you just divide 145 by two and get 72.50 so you add them together at get 362.50

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Consider the expression 25 – 10 ÷ 2 + 3.

Tems11 [23]

Given:

The expression is:

$25-10\div 2+3$

To find:

Part A: The expression using parentheses so that the expression equals 23.

Part B: The expression using parentheses so that the expression equals 3.

Solution:

Part A:

In option A,

$(25-10)\div 2+3=15\div 2+3$

$(25-10)\div 2+3=7.5+3$ [Using BODMAS]

$(25-10)\div 2+3=10.5$

In option B,

$25-10\div (2+3)=25-10\div 5$

$25-10\div (2+3)=25-2$ [Using BODMAS]

$25-10\div (2+3)=23$

In option C,

$(25-10)\div (2+3)=15\div 5$

$(25-10)\div (2+3)=3$

In option D,

$25-(10\div 2)+3=25-5+3$

$25-(10\div 2)+3=28-5$ [Using BODMAS]

$25-(10\div 2)+3=23$

After the calculation, we have $25-10\div (2+3)=23$ and $25-(10\div 2)+3=23$ .

Therefore, the correct options are B and D.

Part B: From part A, it is clear that

$(25-10)\div (2+3)=3$

Therefore, the correct option is C.

8 0

3 years ago

Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)

USPshnik [31]

See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
$M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) + f(\frac{x_{1} + x_{2} }{2}) + ... + f(\frac{x_{n-1} + x_{n} }{2})]$

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
$M_{4} = \frac{1 - 0}{4} [ f(\frac{0 + \frac{1}{4} }{2}) + f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) + f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]$
$M_{4} = \frac{1}{4} [ f(\frac{1}{8}) + f(\frac{3}{8}) + f(\frac{5}{8}) + f(\frac{7}{8})]$

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
$M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]$

$M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]$

M₄ = 1/4 · (2 - 478/512)
= 0.2666

Hence, the area of the region bounded by y = x³ and y = x is approximately 0.267 square units.

6 0

3 years ago

The ten's digit of a two digit number is 1 more than 4 times the units' digit. if 63 is subtracted from the number, the order of

ser-zykov [4K]

Let x be the digit in the tens place and y be the digit in the ones place.
so, the digit is xy

The ten's digit of a two digit number is 1 more than 4 times the units' digit.
x = 4y + 1

63 is subtracted from the number, the order of the digits is reversed
10x + y - 63 = 10y + x
9x - 9y = 63

x = 4y + 1 ------------ (1)
9x - 9y = 63 ---------- (2)

Sub (1) into (2)
9(4y + 1) - 9y = 63
36y + 9 - 9y = 63
27y = 63 - 9
27y = 54
y = 2 ------- sub into (1)

x = 4(2) + 1 = 9

x = 9, y = 2
The number is 92

3 0

3 years ago

What is double of 16

m_a_m_a [10]

Answer:

Step-by-step explanation:

16+16=32

or you can say 16*16=32

8 0

3 years ago

Read 2 more answers

In ΔPQR, the measure of ∠R=90°, the measure of ∠P=26°, and PQ = 8.5 feet. Find the length of QR to the nearest tenth of a foot.

Vitek1552 [10]

Answer:

3.7feet

Step-by-step explanations

Using the sin rule

A/sin a = B/sin b

Let A = PQ = 8.5feet

B = QR = x feet

a = R = 90°

b = P = 26°

Substitute the values into the Sin rule

8.5/sin90 = x/sin26

8.5×sin 26 = x × sin 90

8.5×0.4383 = x× 1

3.7255 = x

Hence the length of QR to the nearest tenth 3.7feet

5 0

3 years ago

Read 2 more answers