Answer:
Claim : men weigh of wild jackalopes is 69.9
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Test statistic = −2.447085
P value = 0.0174
Conclusion :
Fail to Reject the Null hypothesis
Step-by-step explanation:
From the question given :
The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Using calculator :
Sample mean (x) = 66
Sample standard deviation (s) = 12.345
The test statistic t :
(x - μ) / (s/√n)
n = sample size = 60
(66 - 69.9) / (12.345 / √60)
t = −2.447085
P value at α 0.01, df = 59 is 0.0174
Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null
Answer:
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rad 128 can be broke into 64*2
square root of 64 is 8, times -5,
which leaves -40rad2
