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Ksenya-84 [330]
3 years ago
10

Of 3,000 pet owners surveyed 9% purchased their pets from a pet store how many pets were purchased from a pet store

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0
9\%\cdot 3,000 = \frac{9}{100}\cdot 3,000 = 9\cdot 30 = 270
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1 1/4 - 1/3 = 15/24 - ??
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Step-by-step explanation:

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What is the next term in the sequence
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-5/2

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The next term will be,

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Step-by-step explanation:

<em><u>I </u></em><em><u>thin</u></em><em><u>k</u></em><em><u> </u></em><em><u>mode</u></em><em><u>,</u></em><em><u>range</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>median</u></em><em><u> </u></em><em><u>dpo</u></em><em><u> </u></em><em><u>ako</u></em><em><u> </u></em><em><u>sure</u></em>

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3 years ago
Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t​
juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t  ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

 

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