<span>It looks like I could substitute the x=2y-1. Into 2x+y=3 2(2y-1)+y=3 4y-2+y=3 5y=5 y=1 x=2(1)-1 x=1 </span><span> (1,1) CHECK 2x+y=3 2(1)+(1)=3 2+1=3 3=3 Left hand side=Right hand side Check other equation x=2y-1 1=2(1)-1 1=1 </span><span>Therefore the solution is (1,1). Since the left hand side= right hand side in each equation</span>
