Answer:
Total surface area : 733
The shape of the base is a rectangle with sides 11 in. and 12 in.
Step-by-step explanation:
The shape of the base is a rectangle with sides 11 in. and 12 in.
The surface area is the sum of the areas of the 5 sides.
Area of the base = 11*12 = 132
Area of the two triangles = (11*16)/2 = 88
Area of the back rectangle = 192
The theorem of Pitagora to find the oblique side: square root of (11*11 + 16*16)= 19.42 in.
So the area of the oblique face: 19.42* 12 = 233 (almost :) )
So total surface area: 132 + 88*2+192+233= 733 square in
Answer:
211 text messages
Step-by-step explanation:
20+(m•0.10)=41.10
41.1-20=21.1÷0.1=211
By using the AAA congruence property of Triangles, △aec≅△deb is proved
It is given two triangles, Δaec and Δdeb, where e is the common point known as the midpoint of ad
Also, it is given that,
ca ║db
We need to prove that, △aec≅△deb
Then we'll use AAA congruence property of Triangles to prove the situation
As ca ║db
then, ∠cae = ∠ebd (Alternate angles)
∠ace = ∠edb (Alternate angles)
and ∠aec = ∠deb (common angles)
Thus, by AAA congruence property, △aec≅△deb
Hence, proved
To learn more about, congruence property, here
brainly.com/question/2039214
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Answer:
197 leis left over
Step-by-step explanation:
14 times 212 = 2968
2968/30 = 98.93
212 times 0.93 = 197
98 packages and 197 leis left over
