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Irina18 [472]
3 years ago
12

Two number cubes are rolled. What is the probability of rolling a sum of 9 or a sum that is even?

Mathematics
2 answers:
Murljashka [212]3 years ago
8 0

Well I don't know !
Let's figure it out together.

Each cube can land in 6 different ways, so the total number
of possible results with two cubes is (6 x 6) = 36 .

Now we need to figure out how many of those 36 possibilities
meet your specifications ... either 9 or any even number.

Ways to make 9 :

3 . . . 6
6 . . . 3
4 . . . 5
5 . . . 4

Four ways to make 9.
____________________________

Ways to make an even number:

1 . . . 1
3 . . . 1
1 . . . 3
2 . . . 2
5 . . . 1
1 . . . 5
6 . . . 2
2 . . . 6
6 . . . 4
4 . . . 6
6 . . . 6

Eleven ways to make an even number.
_____________________

Total number of ways to succeed = (4 + 11) = 15 ways

So the probability of succeeding (rolling 9 or an even number)
is

               15 / 36  =  5 / 12  =  0.41666... =  (41 and 2/3) % .

elixir [45]3 years ago
5 0
Two dice are thrown and the only possibilities are rolling 2-12. we are trying to find the probability of rolling a 2,4,6,8,9,10,12
7 out of 11 is the probability of rolling a 9 or an even
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Assuming that the equations define x and y implicitly as differentiable functions x=f(t),y=g(t) find the slope of the curve x=f(
Mumz [18]
The given equations are
x(t+1)-4t \sqrt{x} =9            (1)
2y+4y^{3/2}=t^{3}+t           (2)

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x=9 \\ 2y+4y^{3/2}=0 \,\,=\ \textgreater \ \, y(1+2 \sqrt{y} )=0 \,=\ \textgreater \ \,y=0

Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
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x'(0) + x(0) - 4√x(0) = 0
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x'(0) = 3
Here, x' means \frac{dx}{dt}.

Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
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Because \frac{dy}{dx} = \frac{dy}{dt} / \frac{dx}{dt}, obtain
\frac{dy}{dx} |_{t=0}\, =  \frac{1/2}{3}= \frac{1}{6}

Answer:
The slope of the curve at t=0 is 1/6.



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