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3 years ago

I don't understand how to find the volume of these shapes.

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

4 0

Answer:

It tells you in the book all you have to do is plug the numbers in the right spots

These are the volumes that it gives you. All you have to do is plug in the numbers

v= 1/2bh

v= bh

v = Bh

Step-by-step explanation:

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Pi/6 is the reference angle for: 3pi/6 5pi/6 13pi/6 8pi/6

Elanso [62]

Answer:

$\frac{5\pi}{6}, \frac{13\pi}{6}$

Step by step

Remember, a reference angle is a positive acute angle that represents an angle θ of any measurement.

$\frac{3\pi}{6}=90^\circ$ , then its reference angle is $\frac{\pi}{2}$

$\frac{5\pi}{6}=150^ \circ$ is in the second cuadrant, then its reference angle is $180^ \circ -150^{\circ}=30^{\circ}=\frac{\pi}{6}$

$\frac{13\pi}{6}=390^\circ=360^\circ+30^\circ$ , then it is in the first cuadrant and the reference angle is $30^\circ =\frac{\pi}{6}$ .

$\frac{8\pi}{6}=240^\circ$ and it is in the third cuadrant, then its reference angle is $240^\circ -180^\circ=60^\circ=\frac{\pi}{3}$

5 0

3 years ago

If it takes a hoses to fill a tank in b minutes, how many hoses will it take to fill it in c

forsale [732]

In the terms it’s none of them because this is way to confusing

8 0

2 years ago

The candle factory made 498 red candles and 204 white candles each day. About how many candles did the factory make in a day alt

stiv31 [10]

Answer:

about 700

Step-by-step explanation:

you add 204 + 498=

4 0

2 years ago

Read 2 more answers

Find the derivative of the function f(x) = (x3 - 2x + 1)(x – 3) using the product rule.

julsineya [31]

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

$f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Now, we distribute the expression of f(x) and find the derivative afterwards.

$f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0

3 years ago

Which of the following best describes the pattern in the diagram as you move from left to right?

olga_2 [115]

The answer is a, it adds one block

5 0

3 years ago