Answer:
2x^2 + 2y^2 + 2z^2
Step-by-step explanation:
x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2
First step is to put all the same ones together
( FYI, xy and yx is the same thing, just like how
2 x 3 and 3 x 2 is the same thing) this time I'll bracket the groups to make it easier on the eyes
(x^2 +x^2) + (xy - xy) +( y^2 + y^2) + (yz - yz) +
(z^2 +z^2) + (zx - zx)
2x^2 + 2y^2 + 2z^2
All the others just cancel themselves out, for example, xy-xy
When anything minus themselves it will become 0
Answer:
1/5,3/10
Step-by-step explanation:
just look at the picture
Answer: 20 22 24 would be all three of your integers, adn 24 would be the greatest one
Step-by-step explanation:
If you would like to solve 4 + 3/5 * (15 + 2x) = 25 for x, you can do this using the following steps:
4 + 3/5 * (15 + 2x) = 25
3/5 * (15 + 2x) = 25 - 4
9 + 6/5 * x = 21
6/5 * x = 21 - 9
6/5 * x = 12 /*5/6
x = 12 * 5/6
x = 10
The correct result would be x = 10.
Step-by-step explanation:
F(2)=3(2)²-7
=5
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