Numbers containing decimals that are not terminating or recurring .
The answer would be the second one
Isolate x by adding 8 to both sides.
3 = x/3
Then, multiply by 3 on both sides.
9 = x
To prove that this is right, you can imput 9 into the equation and it equals -5.
prime factor stuff.. 32 = 8*4 = (4*2)*(2*2) = (2*2*2)*(2*2)
3 √(2*2*2*2*2*x*x*x*x*z) = 3 √(2²*2²*2*x²*x²*z)
It's a square root so move one of each pair outside the radical.
3*2*2*x*x √(2*z)
12x² √(2z)
3/20 = x/400,
cross multiply
so 20x = 3(400)
20x = 1200
x = 60
