Ask question

Ask question

All categories

3 years ago

13

Which function represents a translation of the parent cubic function 8 units to the left? h(x) = x3 + 8 h(x) = x3 – 8 h(x) = (x

+ 8)3 h(x) = (x – 8)3

2 answers:

Irina-Kira [14]3 years ago

8 0

Answer:

h(x)=(x+8)3

Step-by-step explanation:

Ksju [112]3 years ago

7 0

Using the definition of the Vertical shifts of graphs of the function :

"Suppose c>0,

To graph y=f(x)+c, shift the graph of y=f(x) upward c units.

To graph y=f(x)-c, shift the graph of y=f(x) downward c units"

Again we recall the definition of Horizontal shifts of graphs:

" suppose c>0,

the graph y=f(x-c), shift the graph of y=f(x) to the right by c units

the graph y=f(x+c), shift the graph of y=f(x) to the left by c units. "

consider $f(x)=x^3$ is the parent function.

$h(x)=x^3+8$ shifts the graph $f(x)=x^3$ upward by 8 units

$h(x)=x^3-8$ shifts the graph $f(x)=x^3$ downward by 8 units

$h(x)=(x+8)^3$ shifts the graph $f(x)=x^3$ left by 8 units

$h(x)=(x-8)^3$ shifts the graph $f(x)=x^3$ right by 8 units.

You might be interested in

kvv77 [185]

Option C: $5 x(4 x+7)(3 x+2)$ is the possible expressions for length, width and height of the prism.

Explanation:

The volume of the rectangular prism is $60 x^{3}+145 x^{2}+70 x$

To determine the length, width and height of the rectangular prism, let us factor the expression.

Thus, factoring 5x from the expression, we have,

$5 x\left(12 x^{2}+29 x+14\right)$

Let us break the expression $12 x^{2}+29 x+14$ into two groups, we get,

$5x[\left(12 x^{2}+8 x\right)+(21 x+14)]$

Factoring 4x from the term $12 x^{2}+8 x$ , we get,

$5x[4 x(3 x+2)+(21x+14)]$

Similarly, factoring 7x from the term $21 x+14$ , we get,

$5x[4 x(3 x+2)+7(3x+2)]$

Now, let us factor out $3x+2$ , we get,

$5 x(4 x+7)(3 x+2)$

Hence, the possible expressions for length, width and height of the prism is $5 x(4 x+7)(3 x+2)$

Therefore, Option C is the correct answer.

8 0

3 years ago

18000lb greater then or less then 9T

Alla [95]

It is equal because every 2000 pounds is 1 ton and 18000lb divided by 2000 equals 9.

5 0

3 years ago

Read 2 more answers

The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) for Determine

salantis [7]

The question is incomplete. Here is the complete question.

The probability density function of the time to failure of an electronic component in a copier (in hours) is

$f(x)=\frac{e^{\frac{-x}{1000} }}{1000}$

for x > 0. Determine the probability that

a. A component lasts more than 3000 hours before failure.

b. A componenet fails in the interval from 1000 to 2000 hours.

c. A component fails before 1000 hours.

d. Determine the number of hours at which 10% of all components have failed.

Answer: a. P(x>3000) = 0.5

b. P(1000<x<2000) = 0.2325

c. P(x<1000) = 0.6321

d. 105.4 hours

Step-by-step explanation: <em>Probability Density Function</em> is a function defining the probability of an outcome for a discrete random variable and is mathematically defined as the derivative of the distribution function.

So, probability function is given by:

P(a<x<b) = $\int\limits^b_a {P(x)} \, dx$

Then, for the electronic component, probability will be:

P(a<x<b) = $\int\limits^b_a {\frac{e^{\frac{-x}{1000} }}{1000} } \, dx$

P(a<x<b) = $\frac{1000}{1000}.e^{\frac{-x}{1000} }$

P(a<x<b) = $e^{\frac{-b}{1000} }-e^\frac{-a}{1000}$

a. For a component to last more than 3000 hours:

P(3000<x<∞) = $e^{\frac{-3000}{1000} }-e^\frac{-a}{1000}$

Exponential equation to the infinity tends to zero, so:

P(3000<x<∞) = $e^{-3}$

P(3000<x<∞) = 0.05

There is a probability of 5% of a component to last more than 3000 hours.

b. Probability between 1000 and 2000 hours:

P(1000<x<2000) = $e^{\frac{-2000}{1000} }-e^\frac{-1000}{1000}$

P(1000<x<2000) = $e^{-2}-e^{-1}$

P(1000<x<2000) = 0.2325

There is a probability of 23.25% of failure in that interval.

c. Probability of failing between 0 and 1000 hours:

P(0<x<1000) = $e^{\frac{-1000}{1000} }-e^\frac{-0}{1000}$

P(0<x<1000) = $e^{-1}-1$

P(0<x<1000) = 0.6321

There is a probability of 63.21% of failing before 1000 hours.

d. P(x) = $e^{\frac{-b}{1000} }-e^\frac{-a}{1000}$

0.1 = $1-e^\frac{-x}{1000}$

$-e^{\frac{-x}{1000} }=-0.9$

${\frac{-x}{1000} }=ln0.9$

-x = -1000.ln(0.9)

x = 105.4

10% of the components will have failed at 105.4 hours.

5 0

4 years ago

John earns $7.50 per hour at his job. Becky's earnings are given by the equation P = 8.25x, where P is her

hodyreva [135]

In 9 hours
john earns $67.5
becky earns $74.25
becky earns $6.75 more than john

4 0

3 years ago

True or false that integers can be negative numbers

lisov135 [29]

Answer:

true

Step-by-step explanation:

5 0

3 years ago