The two numbers are -6 and 7
<em><u>Solution:</u></em>
Given that eight times a number plus five times another number is -13
The sum of two numbers is 1
To find: the two numbers
Let the two numbers be "a" and "b"
From given information,
Eight times a number plus five times another number = -13
eight times a number "a" + five times another number "b" = -13
8a + 5b = -13 ---- eqn 1
Also given that sum of two numbers is 1
sum of two numbers = 1
a + b = 1 ---- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "b"</u></em>
From eqn 2,
a = 1 - b ----- eqn 3
Substitute eqn 3 in eqn 1
8(1 - b) + 5b = -13
8 - 8b + 5b = -13
8 - 3b = -13
-3b = -13 - 8
-3b = -21
<h3>b = 7</h3>
Substitute b = 7 in eqn 3
a = 1 - 7
<h3>a = -6</h3>
Thus the two numbers are -6 and 7
Answer:
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Found this online :)
7x7(12+9) to the power of 3
Step-by-step explanation:
(-6x +3y=9 )×4
( 10x+4y)×3
-24x +12y =36
30x+12y= -18
-24x+12y- (30x+12y)= 36-(-18)
-54x = 54
x= -1
by using 10x +4y = -6
apply x= -1
-10+4y= -6
4y= -6 +10
4y=4
y=1
so the answer is x=-1 and y= 1
Factored form - x= -1/2, -5/4