Question

PLEASE KINDLY SOLVE IT WITH EXPLANATION:)​

Answer 1

Answer:

[D} $5-2\sqrt{6}$

Step-by-step explanation:

$\mathrm{Apply\:Perfect\:Square\:Formula}:$ $\quad \left(a-b\right)^2=a^2-2ab+b^2$

$\left(\sqrt{3}-\sqrt{2}\right)^2=\left(\sqrt{3}\right)^2-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^2$

$=\left(\sqrt{3}\right)^2-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^2$

$=5-2\sqrt{6}$

[RevyBreeze]

Answer 2

Answer:

d) 5 - 2√6

Step-by-step explanation:

We need to simply (√3 - √2)². Assume that √3 is 'a' and √2 is 'b'. At the present time, the given term looks like: (a - b)². And we know that (a - b)² = a² + b² - 2ab. Apply the same rule in (√3 - √2)².

→ (√3)² + (√2)² - 2(√3)(√2)

Square root can be written as ½ and square of ½ means 1 as 1/2 × 2 is 1. So,

→ 3 + 2 - 2√6

→ 5 - 2√6

Option (D) is the correct option among the other options.