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kherson [118]
3 years ago
12

What is the answer please give me the answer

Mathematics
2 answers:
Lena [83]3 years ago
7 0
69.083, Hope this helps
Alex Ar [27]3 years ago
3 0
69 and 83 hundredths
69.83 is the answer
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Please help me i need this right nowpleaseedcd vid,
ExtremeBDS [4]

Answer:5) c= 25.12 cm

6) c= 282.6 m

7) c= 13.188 mi

8) c= 6.28 cm

Step-by-step explanation:

C= 2 x pi x r

Circumference = 2 x 3.14 x radius ( radius is half the diameter of the circle)

4 0
3 years ago
Write 0.63 as a fraction in simplest form.
Annette [7]

63/100?

no te entiendo hablo español bro srry :(

3 0
3 years ago
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Which will result in a difference of squares? (negative 7 x + 4)(negative 7 x + 4) (negative 7 x + 4)(4 minus 7 x) (negative 7 x
nevsk [136]

Answer:

(negative 7 x + 4)(negative 7 x minus 4)

Step-by-step explanation:

Consider two real numbers a and b. A difference of squares involving a and b is usually given as;

a^{2}-b^{2}

The difference of the two squares above can be factored to yield;

(a-b)(a+b)

This implies that in order to have the difference of squares we must have a product involving the difference and the sum of the numbers.

The expression;

(negative 7 x + 4)(negative 7 x minus 4) can also be written as ( 4 - 7x) ( -4 - 7x)

( 4 - 7x) ( -4 - 7x) = ( 4 - 7x) (-1( 4 + 7x)) = -1 *( 4 - 7x) ( 4 + 7x)

Expanding the last expression yields;

-1 (16 + 28x -28x - 49x^2) = -1 (16 - 49x^2) = 49x^2 - 16 which is in deed a difference of squares

3 0
4 years ago
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Drag each triangle to the correct categorie
REY [17]

Answer: what?

Step-by-step explanation:

5 0
3 years ago
Find the first five terms of the sequence in which a1 = 6 and an = –3an – 1 – 12, if n ≥ 2.
KatRina [158]

Answer:

\huge\boxed{6,\ -30;\ 78;\ -246;\ 690}

Step-by-step explanation:

a_1=6\\a_n=-3a_{n-1}-12\qquad n\geq2\\\\\text{Substitute}\ n=2,\ n=3,\ n=4,\ n=5\ \text{to}\ a_n=-3a_{n-1}-12:\\\\\text{for}\ n=2\\\\a_2=-3a_{2-1}-12=-3a_1-12\\\\\text{substitute}\ a_1=6\\\\a_2=-3(6)-12=-18-12=-30\\\\\text{for}\ n=3\\\\a_3=-3a_{3-1}-12=-3a_2-12\\\\\text{substitute}\ a_2=-30\\\\a_3=-3(-30)-12=90-12=78

\text{for}\ n=4\\\\a_4=-3a_{4-1}-12=-3a_3-12\\\\\text{substitute}\ a_3=78\\\\a_4=-3(78)-12=-234-12=-246\\\\\text{for}\ n=5\\\\a_5=-3a_{5-1}-12=-3a_4-12\\\\\text{substitute}\ a_4=-246\\\\a_5=-3(-246)-12=702-12=690

8 0
4 years ago
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