![\qquad \tt \rightarrow \:Domain = [-9, -1]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3ADomain%20%3D%20%5B-9%2C%20-1%5D)
![\qquad \tt \rightarrow \:Range = [-1 , 3]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3ARange%20%3D%20%5B-1%20%2C%203%5D)
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Domain = All possible values of x for which f(x) is defined
[ generally the extension of function in x - direction ]
Range = All possible values of f(x)
[ generally the extension of function in y - direction ]
![\qquad \tt \rightarrow \: domain = [ - 9, -1]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20domain%20%3D%20%5B%20-%209%2C%20-1%5D)
![\qquad \tt \rightarrow \: range= [ -1,3]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20range%3D%20%5B%20-1%2C3%5D)
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Answer is -2(3p+10)
hope this helps :)
1. Angle addition postulate (this could be wrong)
2. Definition of bisect
3. Definition and postulate
4. Screenshot at the bottom
Last one I can't help, my bad.
1) 330
2) 172
3) 172
4) 99
5) 142
You place the smaller number or single number on the left side of the box then on top of the box for the first square you would take the first number of your two digit number turn that into a whole number then the second number you would put on top of the second box then just multiply them both separately then add them together.
Example number one: first multiply 5x60 you get 300 for the first box then you multiply 5x6 you get 30 so then you would add the 300 and the 30 to get 330. Hope this helps :)
