The question in English is A prism with a rhombus pedestal has a diagonal length of 24 cm and 10 cm. if the height of the prism is 8 cm, then the surface area of the prism is
we know that h=8 cm D=24 cm d=10 cm Area of the rhombus=(d*D)/2=10*24/2=120 cm² now calculate the side of the rhombus with Pythagorean theorem L=√(d/2)²+(D/2)²=√(10/2)²+(24/2)²=13 cm surface area of the prism=[120*2+13*8*4]=656 cm²
the answer is 656 cm²
the answer in Malay
<span>kami tahu itu </span>h=8 cm D=24 cm d=10 cm Kawasan rombus=(d*D)/2=10*24/2=120 cm² <span>kini mengira sisi rombus dengan teorem Pythagoras </span>L=√(d/2)²+(D/2)²=√(10/2)²+(24/2)²=13 cm kawasan permukaan prisma=[120*2+13*8*4]=656 cm²
15) factor out cos: cos(x)(sin(x)+1)=0 Now this is true when either cos(x)=0 (x=pi/2 and 3pi/2) Or when sin(x)=-1 (x=3pi/2) So it's solutions are pi/2 and 3pi/2
