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3 years ago

Find the next three terms of the sequence 80, –160, 320, –640, . . .

Mathematics

2 answers:

posledela3 years ago

8 0

1280, -2560, 5120

Multiply the preceding term by -2 and

liraira [26]3 years ago

5 0

Each term is multiplied by -2 to get the next term.

The next numbers would be 1,280, -2560, and 5120.

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In ΔGHI, the measure of ∠I=90°, the measure of ∠G=62°, and GH = 96 feet. Find the length of IG to the nearest tenth of a foot.

alexandr402 [8]

Answer:

45.1feet

Step-by-step explanation:

Given the following

∠I=90°

∠G=62°, and

GH = 96 feet = Hypotenuse

Required

IG = Adjacent side

Using the SOH CAH TOA identity

Cos theta = Adj/hyp

Cos 62 =IG/96

IG = 96cos62

IG = 96(0.4695)

IG = 45.1feet

Hence the length of IG to the nearest tenth is 45.1feet

6 0

2 years ago

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Which of the following represents a value greater than 50,000 but less than 60,000

saul85 [17]

Answer:

Any number between them both

7 0

2 years ago

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Please help!! thank you.

Zina [86]

(A) Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ is:

$(-2x^{3}+x-5)(x^{3}-3x-4)$

$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$

$=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)$

$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$

$=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20$

$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$

(B) Yes.

Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ = Product of $x^{3}-3x-4$ and $-2x^{3}+x-5$ because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.

5 0

2 years ago

Plz help me. I need help fast

Margaret [11]

I think is C

Let me know!

5 0

2 years ago

Please help me with this homework

3241004551 [841]

Answer:

Step-by-step explanation:

The pythagorean theorem shows a^2+b^2=c^2.

a=8, b=15, c= the unknown distance

8^2+15^2=c^2

7 0

1 year ago