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Aleks04 [339]
3 years ago
5

Hiro used 60 square inches of fabric.To make a triangular sail for his model sailboat. The base of the sail was 8 inches what wa

s the height of the sail?
Mathematics
1 answer:
andrey2020 [161]3 years ago
7 0

Answer:

Height of the sail is 15 inches.

Step-by-step explanation:

Given:

Area of the fabric = 60\ in^2

Base of the sail = 8 in.

We need to find the height of the sail.

Solution:

Let the height of the sail be 'h'.

Now we know that;

Area of Triangle is given by half time base multiplied by the height.

framing in equation form we get;

60=\frac12\times8\times h\\\\60=4h

Dividing both side by 4 we get;

\frac{60}{4}=\frac{4h}{4}\\\\h= 15\ in

Hence height of the sail is 15 inches.

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263/4 options 65r2 64r7 65 65r3
Reika [66]

Answer:

65R3

Step-by-step explanation:

260/4 is a whole number, so then there would be a remainder 3. The only one with a r3 is D.

Hope this helps :D

4 0
2 years ago
g A coffee-dispensing machine is supposed to deliver eight ounces of liquid into each paper cup, but a consumer believes that th
kap26 [50]

Answer: Reject the eight- ounces claim.

Step-by-step explanation:

For left tailed test , On a normal curve the rejection area lies on the left side of the critical value.

It means that if the observed z-value is less than the critical value then it will fall into the rejection region other wise not.

As per given ,

Objective : A coffee-dispensing machine is supposed to deliver eight ounces of liquid or less.

Then ,

H_0: \mu=8\\\\H_a: \mu , since alternative hypothesis is left-tailed thus the test is an left-tailed test.

the critical value for z for a one-tailed test with the tail in the left end is -1.645 and the obtained value is -1.87.

Clearly , -1.87 < -1.645

⇒ -1.87 falls under rejection region.

⇒  Decision : Reject null hypothesis.

i.e. we reject the eight- ounces claim.

6 0
3 years ago
PLEASE HELP!
hram777 [196]

Answer:

<em>Triangle ABC is like a reflection to triangle AYZ.  They are the same size and line AB are the same as line YA</em>

Step-by-step explanation:

5 0
2 years ago
What is the area of a trapezoid if the base is 5, 17, 5 and height is 4
Snowcat [4.5K]

Answer:

Step-by-step explanation:

Trapezoid

Solve for area

A=44

a Base  

5

b Base  

17

h Height  

4

7 0
3 years ago
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
2 years ago
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