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grin007 [14]
3 years ago
9

Software that interprets command from mouse is a

Computers and Technology
1 answer:
balu736 [363]3 years ago
3 0
I think it would be me because i interpret command from a mouse in my hole.
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Pray to God and ask him for help in life. May God bless you

Explanation:

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Which character is used to begin a comment?
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# is used to begin a comment.
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Write the Flowchart to find Even number between 1 to 50<br>​
ASHA 777 [7]

Answer:

See attachment for flowchart

Explanation:

Required

Flowchart to fine even from 1 to 50

The flowchart has been attached.

The rough algorithm (explanation) of the flowchart is as follows.

1. Start

2. Initialize num to 1

3. Check if num is less than or equal to 50

  3.1 If yes

      3.1.1 Check if num is even

      3.1.1.1 If yes

         3.1.1.2 Print num

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 3.2 If num is greater than 50

    3.2.1 Stop

4. Goto 3

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3 years ago
Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl
Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

    small = num1

    if num1 > num2:

         small = num2

    for i in range(1, small+1):

         if((num1 % i == 0) and (num2 % i == 0)):

              gcd = i

    print("The GCD is "+ str(gcd))

def LCM(num1,num2):

    big = num2  

    if num1 > num2:

         big = num1

    while(True):

         if((big % num1 == 0) and (big % num2 == 0)):

              lcm = big

              break

         big = big+1

     print("The LCM is "+ str(lcm))

 print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

    small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

<em>     if num1 > num2: </em>

<em>          small = num2 </em>

The following iteration determines the GCD of num1 and num2

<em>     for i in range(1, small+1): </em>

<em>          if((num1 % i == 0) and (num2 % i == 0)): </em>

<em>               gcd = i </em>

This line prints the GCD

    print("The GCD is "+ str(gcd))

   

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

    big = num2  

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

<em>     if num1 > num2: </em>

<em>          big = num1 </em>

The following iteration continues while the LCM has not been gotten.

    while(True):

This if statement determines the LCM using modulo operator

<em>          if((big % num1 == 0) and (big % num2 == 0)): </em>

<em>               lcm = big </em>

<em>               break </em>

<em>          big = big+1 </em>

This line prints the LCM of the two numbers

     print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

<em></em>

<em>See attachment for more structured program</em>

Download txt
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Since ESPN been telecasted through air with customer login with minimum subscription fees so end user easily login n watch the match online and live telecast. Moreover end user can watch old or missed match from archive library on its own time.

ESPN is subscription channel are also available as bundle option in hot star amazon prime video.

<u>ESPN upgrade</u>:

ESPN telecast match on season basic such as football, cricket extra. ESPN very frequently upgrade the match schedule and old archives. Sports person interviews n performance of software also is upgraded to end users.

4 0
3 years ago
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