Answer:
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
Explanation:
The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).
Where f(x) is frequency of character x.
Lets consider the scenario when
f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005
Please see attachment for image showing the steps of construction of Huffman tree:- see attachment
From the Huffman tree created, we can see that endcoding e() of each character are as follows:-
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
e(e) = 11110
e(f) = 11111
So we can see that maximum length of encoding is 5 in this case.
Answer: Formulating your brief
Explanation:
The key stage that involves considering design options is formulating one's brief.
The aim of "Formulating Your Brief" is simply a way to determine the context in which a particular work will be to be undertaken after which the aim is then defined. It can either be formal or informal.
Answer:
True
Explanation:
A Domain Name Service comprises of computer servers that carries a database of public IP addresses and their related human-readable domain names/hostnames, it receives query as hostnames and helps to translates those human-readable domain names/hostnames into IP addresses that computers and routers understand.
Answer:
Vehicle forensics is a process that yields a myriad of data potentially helpful to all kinds of investigations, from law enforcement cases, to insurance fraud, to accident reconstruction. Many newer vehicles (generally 2008 and newer) are equipped with an infotainment system.
Answer:
22
Explanation:
1. We are going to have at hand 32 Enqueue Operation, with 10 from front and 15 dequeue and 5 empty queue operation
2. You dequeued total number of 15-5 =10 elements since 5 dequeue did not change the state of the queue, so invariably 10 dequeue is done.
3. Next is to enqueued a total of 32 elements.
Enqueue Operation do not change the state(and Size) of the queue, and can be ignored.
4. To arrive at the Total Size of queue, we will have 32-10 = 22 at the end
Answer : 22 because its a 5 dequeue Operations.
