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s344n2d4d5 [400]

3 years ago

10

Help with this one!!! Show steps pls :)

2 answers:

olga2289 [7]3 years ago

8 0

Answer: $29.38

Step-by-step explanation:

To calculate a tax of a dollar value, use this formula:

[original dollar value] * [tax percentage] = [tax]

Your original dollar value is $734.50, and your tax percentage is 4%.

734.5 * 0.04. Brett will pay $29.38 in tax.

Elza [17]3 years ago

4 0

Answer:

$29.38

Step-by-step explanation:

$734.50

Sales tax is 4% --> .04

734.50 x .04 = 29.38

He will pay $29.38

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Please help me with this math

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Step-by-step explanation:

2(3p+4)

Let p=2

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3 years ago

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This is 5th grade math pls help

Mamont248 [21]

Answer:

He can make 20 cakes

Step-by-step explanation:

Im in highshool so I know the answer

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2 years ago

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The boundary of a lamina consists of the semicircles y = 1 − x2 and y = 16 − x2 together with the portions of the x-axis that jo

oksano4ka [1.4K]

Answer:

Required center of mass $(\bar{x},\bar{y})=(\frac{2}{\pi},0)$

Step-by-step explanation:

Given semcircles are,

$y=\sqrt{1-x^2}, y=\sqrt{16-x^2}$ whose radious are 1 and 4 respectively.

To find center of mass, $(\bar{x},\bar{y})$ , let density at any point is $\rho$ and distance from the origin is r be such that,

$\rho=\frac{k}{r}$ where k is a constant.

Mass of the lamina=m= $\int\int_{D}\rho dA$ where A is the total region and D is curves.

then,

$m=\int\int_{D}\rho dA=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}rdrd\theta=k\int_{}^{}(4-1)d\theta=3\pi k$

Now, x-coordinate of center of mass is $\bar{y}=\frac{M_x}{m}$ . in polar coordinate $y=r\sin\theta$

$\therefore M_x=\int_{0}^{\pi}\int_{1}^{4}x\rho(x,y)dA$

$=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}(r)\sin\theta)rdrd\theta$

$=k\int_{0}^{\pi}\int_{1}^{4}r\sin\thetadrd\theta$

$=3k\int_{0}^{\pi}\sin\theta d\theta$

$=3k\big[-\cos\theta\big]_{0}^{\pi}$

$=3k\big[-\cos\pi+\cos 0\big]$

$=6k$

Then, $\bar{y}=\frac{M_x}{m}=\frac{2}{\pi}$

y-coordinate of center of mass is $\bar{x}=\frac{M_y}{m}$ . in polar coordinate $x=r\cos\theta$

$\therefore M_y=\int_{0}^{\pi}\int_{1}^{4}x\rho(x,y)dA$

$=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}(r)\cos\theta)rdrd\theta$

$=k\int_{0}^{\pi}\int_{1}^{4}r\cos\theta drd\theta$

$=3k\int_{0}^{\pi}\cos\theta d\theta$

$=3k\big[\sin\theta\big]_{0}^{\pi}$

$=3k\big[\sin\pi-\sin 0\big]$

$=0$

Then, $\bar{x}=\frac{M_y}{m}=0$

Hence center of mass $(\bar{x},\bar{y})=(\frac{2}{\pi},0)$

3 0

2 years ago

In Evan's math class, there are 7 boys and 10 girls. Which of the following is the ratio of boys to girls in Evan's math class?

Taya2010 [7]

Answer:

7/17

Step-by-step explanation:

3 0

3 years ago

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Theresa has a credit card that uses the average daily balance method. For the first 12 days of one of her billing cycles, her ba

katrin [286]

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$\frac{350\times12+520\times19}{12+19} = \frac{4200+9880}{31} \\ \\ = \frac{14080}{31} =$454.19$

Therefore, the interest charge on Theresa for the biling cycle is given by:

$\frac{454.19(0.14)}{12} = \frac{63.59}{12} \\ \\ =\$5.30$

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3 years ago

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