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3 years ago

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A soup can has a diameter of 8 cm and a height of 12 cm. What is the volume of the soup can? Use 3.14 for Pi. A cylinder has a h

eight of 12 centimeters and diameter of 8 centimeters. 192.00 cubic centimeters 301.44 cubic centimeters 602.88 cubic centimeters 2,411.52 cubic centimeters

2 answers:

Alik [6]3 years ago

5 0

Answer:

602.88

Step-by-step explanation:

seropon [69]3 years ago

4 0

Answer:

602.88

Step-by-step explanation: i got this right on my quiz yw <3

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9th grade alg 1<br><br> number 43 and work please!

Darya [45]

Answer:

The rule is y = -7x + 5

→ Other values of x;

-9

→ Other values of y;

5
-2
-9
-12
28
68
-170

Step-by-step explanation:

» Take points (1, -2) and (3, -12) from the table.

☑ General equation of a line is y = mx + c

m is the slope
c is y-intercept

✍<u> </u><u>F</u><u>o</u><u>r</u><u> </u><u>s</u><u>l</u><u>o</u><u>p</u><u>e</u><u>,</u><u> </u><u>m</u><u> </u>:

${ \tt{slope = \frac{ - 12 - 2}{3 - 1} }} \\ \\ { \tt{slope = \frac{ - 14}{2} }} \\ \\ { \tt{m = - 7}}$

✍<u> </u><u>For</u><u> </u><u>y-intercept</u><u>,</u><u> </u><u>c</u><u> </u>:

${ \tt{y = mx + c}}$

» Taking point (1, -2):

${ \tt{ - 2 = (1 \times - 7) + c}} \\ { \tt{c = - 2 + 7}} \\ { \tt{c = 5}}$

${ \boxed{ \tt{y = - 7x + 5}}}$

3 0

3 years ago

Read 2 more answers

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

PICTURE PLEASE HELP.

aksik [14]

By pythagorean theorem

a^2+b^2=c^2

We can find that PL is 12.65

and then by altitude theorem

MA*LA=PA^2

we can find the value of MA

12MA=16

MA=1.33

then by the pythagorean theorem

we can use to find PM

MA^2+PA^2=PM^2

so PM=4.22

then to find the are you multiply length by width

PM*PL

12.65*4.22

So the area is 53.38

8 0

4 years ago

Math Help!! Can anyone please help me?

ehidna [41]

I dont know because to complicated

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3 years ago

The distance that a jogger travels at a constant speed of 6.5 miles per hour can be modeled by the linear function f(x)=6.5x, wh

Sophie [7]

Domain : [ -infinite , infinite [
graph should be going up diagonally .

7 0

4 years ago