Answer:
D^2 = (x^2 + y^2) + z^2
and taking derivative of each term with respect to t or time, therefore:
2*D*dD/dt = 2*x*dx/dt + 2*y*dy/dt + 0 (since z is constant)
divide by 2 on both sides,
D*dD/dt = x*dx/dt + y*dy/dt
Need to solve for D at t =0, x (at t = 0) = 10 km, y (at t = 0) = 15 km
at t =0,
D^2 = c^2 + z^2 = (x^2 + y^2) + z^2 = 10^2 + 15^2 + 2^2 = 100 + 225 + 4 = 329
D = sqrt(329)
Therefore solving for dD/dt, which is the distance rate between the car and plane at t = 0
dD/dt = (x*dx/dt + y*dy/dt)/D = (10*190 + 15*60)/sqrt(329) = (1900 + 900)/sqrt(329)
= 2800/sqrt(329) = 154.4 km/hr
154.4 km/hr
Step-by-step explanation:
Answer:
yep
Step-by-step explanation:
nice
Answer:
B
Step-by-step explanation:
Supplementary angles sum to 180°, hence
3x + 9 + 2x + 2 = 180, that is
5x + 11 = 180 ( subtract 11 from both sides )
5x = 169 ( divide both sides by 5 )
x = 33.8
Hence the smaller angle has a measure of
2x + 2 = (2 × 33.8) + 2 = 67.6 + 2 = 69.6° → B
R(p) = -15p² + 200p + 10,000
To find the maximum of the function, we take the first derivative and equate to 0:
R'(p) = -30p + 200
0 = -30p + 200
p = 6.67
A price of $6.67 will maximize revenue.
The chef can make 25 cakes
Explaintion:
There is a few ways to solve this but an app say way is to
Multiply the 15 gallons by the denominator of the fraction then divide by 3
So 15x5=75
75/3=25
Therefore the chef can make 25 cakes
