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3 years ago

What is the selling price if the original cost is $145 and the markup is 150%? PLEASE HELP!! :(

Mathematics

1 answer:

katovenus [111]3 years ago

7 0

Answer:

$362.50

Profit: $217.50

Step-by-step explanation:

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

The perimeter of a rectangle garden is 348 feet if the length of the garden is 93 feet what is the width?

Ber [7]

The width is 81 feet.
93(2)+81(2)=348

3 0

3 years ago

Read 2 more answers

Simplify: <br>5√3+4√12-2√75

svlad2 [7]

Answer:

8 + $5\sqrt{3}$ $-10\sqrt{7}$

Step-by-step explanation:

i just wrote $5\sqrt{3}$ as a decimal

times 2 with $4\sqrt{1}$ and

times 5 with $-2\sqrt{7}$

i might be wrong but hope this helps

3 0

4 years ago

Which expression is equivalent to 63 + 27?

azamat

The answer would be B.

5 0

3 years ago

What is the midpoint of the vertical line segment graphed below? (2, 4), (2, -9) A. (4, -5). B. (2, -5/2). C. (2, -5). D. (4, 5/

omeli [17]

Answer:

B. $(2, -\frac{5}{2})$

Step-by-step explanation:

Given:

(2, 4) and (2, -9)

Required:

Midpoint of the vertical line with the above endpoints

Solution:

Apply the midpoint formula, which is:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Where,

(2, 4) = (x_1, y_1)

(2, -9) = (x_2, y_2)

Plug in the values into the equation:

$M(\frac{2 + 2}{2}, \frac{4 + (-9)}{2})$

$M(\frac{4}{2}, \frac{-5}{2})$

$M(2, -\frac{5}{2})$

8 0

3 years ago