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3 years ago

M x+ B = y solve for B A x+ B y = C solve for x Bh/2 = A, solve for h

Mathematics

1 answer:

quester [9]3 years ago

5 0

Step-by-step explanation:

Mx+B=y

B=y-Mx

Ax+By=C

Ax=C-By

Ax/A=C-By/A

x=C-By/A

Bh/2=A

2 x Bh/2=A x 2

Bh=2A

Bh/B=2A/B

h=2A/B

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There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,

lys-0071 [83]

According to given information there are :

5 red balls

4 blue balls

6 yellow balls

10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{total \: red \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{25}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{1}{5}$

<h3>2. what is the probability that the ball chosen is blue ?</h3>

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{total \: blue \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{25}$

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{total \: yellow\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{25}$

<h3>4. what is the probability that the ball chosen is green ?</h3>

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{total \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{25}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{2}{5}$

<h3>5. what is the probability that the ball chosen is not green ?</h3>

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{total \: non \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{15}{25}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{3}{5}$

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2 years ago

Given the figure. Find AC.

Angelina_Jolie [31]

Image is missing, so i have attached it.

Answer:

AC = 10sin 40°

Step-by-step explanation:

From the diagram attached, using terms in trigonometric ratio, AC is the opposite side, BC is the adjacent side and AB is the hypotenuse.

Thus, since we want to find AC;

We know that in trigonometric ratios; opposite/hypotenuse = sin θ

In the diagram, θ = 40° and AB = 10

Thus,

AC/10 = sin 40°

Multiply both sides by 10 to get;

AC = 10sin 40°

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3 years ago

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Answer:

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Step-by-step explanation:

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