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3 years ago

M x+ B = y solve for B A x+ B y = C solve for x Bh/2 = A, solve for h

Mathematics

1 answer:

quester [9]3 years ago

5 0

Step-by-step explanation:

Mx+B=y

B=y-Mx

Ax+By=C

Ax=C-By

Ax/A=C-By/A

x=C-By/A

Bh/2=A

2 x Bh/2=A x 2

Bh=2A

Bh/B=2A/B

h=2A/B

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AnnZ [28]

Answer:

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3 years ago

What is the interquartile range of this data? 6 8 9

vladimir1956 [14]

Answer:

Step-by-step explanation:

Just subtract the first quartile form the third quartile.

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32 - 8 = 24 IQR

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SECOND quartile: 20

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3 years ago

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Find three consecutive integers such that the sum of the largest and 5 times the smallest is -244. URGENT

Bad White [126]

Answer:

-39+5(-41)=244

Step-by-step explanation:

Consider 3 consecutive integers: (smallest) x, x+1 and x+2 (largest)

Five times the smallest means 5x

Sum of the largest and five times the smallest means x+2+5x

This sum is -244 means x+2+5x=-244

Solve this equation

x+2+5x=-244

6x+2=-244

6x=-244-2

6x=-246

x=-41

So, smallest number is -41, second is -40 and largest is -39

= -39+5(-41)=244

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3 years ago

(x+5)2−(x−2)=A<br> Need help!

valkas [14]

IF YOUR SOLVING FOR A THE ANSWER WOULD BE A=X+12

IF YOUR SOLVING FOR X IT WOULD BE X=-12+A

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3 years ago

Solve for x. 6x-10≤8 or 1/3 x+6>12

Feliz [49]

The solution is

$x\le 3 \:or \:x>18$

$EXPLANATION$

$6x-10\le 8\: or \frac{1}{3}x+6>12$

We group like terms, to obtain;

$6x\le 8+10\: or \frac{1}{3}x>12-6$

Simplify to get,

$6x\le 18\: or \frac{1}{3}x>6$

We further simplify to get;

$x\le 3\: or x>18$

This can also be rewritten as;

$x\le 3, x>18$

$(-\infty 3] \cup (18,+ \infty)$

This can be represented on the number line as shown in the diagram.

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4 years ago

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